T=distance over speed
T=40m over 9.8ms
T=answer
Answer:
The intensity of the electric field is

Explanation:
The electric field equation is given by:

Where:
- k is the Coulomb constant
- q is the charge at 0.4100 m from the balloon
- d is the distance from the charge to the balloon
As we need to find the electric field at the location of the balloon, we just need the charge equal to 1.99*10⁻⁷ C.
Then, let's use the equation written above.


I hope it helps you!
Metals are giant structures of atoms held together by metallic bonds. “Giant” implies that large but variable numbers of Atoms are involved - depending on the size of the bits of metal. most metals are close packed - that is, they fit as many items as possible into the available volume.
Answer: n=4
Explanation:
We have the following expression for the volume flow rate
of a hypodermic needle:
(1)
Where the dimensions of each one is:
Volume flow rate 
Radius of the needle 
Length of the needle 
Pressures at opposite ends of the needle
and 
Viscosity of the liquid 
We need to find the value of
whicha has no dimensions, and in order to do this, we have to rewritte (1) with its dimensions:
(2)
We need the right side of the equation to be equal to the left side of the equation (in dimensions):
(3)
(4)
As we can see
must be 4 if we want the exponent to be 3:
(5)
Finally:
(6)