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3 years ago

12

Thandy is looking at two cells under the microscope.One is a human cheek cell and the other is a leaf mesophyll cell from a plan

t. Why does thandy need to use a microscope to look at the cells ?

1 answer:

Vanyuwa [196]3 years ago

7 0

Cell are small and us human can't see them with our own eyes. it is in possible to see cell without a microscope

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if the amplitude of sine curve is 4 and the frequency is 1 with no phase shift, what is the function that descirbes this curve?

Vlada [557]

Answer:

y = 4 Sin (2πt)

Explanation:

Amplitude, A = 4

frequency, f = 1

Wave function is given by

y = A sinωt

where, ω is angular frequency

ω = 2 π f = 2 π x 1 = 2π

So, the desired wave function

y = 4 Sin (2πt)

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3 years ago

What condition is necessary for the sustained flow of water in a pipe?

lianna [129]

Pressure difference (voltage)
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3 years ago

A 20-cm-diameter disk emits light uniformly from its surface. 40 cm from this disk, along its axis, is a 16.0-cm-diameter opaque

Marianna [84]

Answer:

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Explanation:

if you round it is correct

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2 years ago

A volt-ampere (va) is the product of the voltage and the ________________ of the electricity on a line.â

zalisa [80]

A volt-ampere is the product of the voltage and the current (measured in amperes) of the electricity on a line. Voltage is electric potential difference in charge between two points in an electrical field. it is measured in volts. while the Current is the flow of electrical charge which is often carried by moving electrons in a wire or a conductor. Current is measured in Amperes.

3 0

2 years ago

A proton is moving in a circular orbit of radius 20 cm under a uniform magnetic field 0.3 t perpendicular to the velocity of the

Vladimir [108]

Answer:

v = 5.75 x 10⁶ m/s

Explanation:

The radius (r) of the circular orbit taken by a charged particle is related to its speed perpendicular to a magnetic field of strength B, and is given by

r = $\frac{mv}{qB}$ --------------(i)

Where,

q = charge of the particle

m = mass of the particle

Making v subject of the formula in equation (i) above gives

v = $\frac{qBr}{m}$ -------------------(ii)

Given;

r = 20cm = 0.2m

B = 0.3T

v = unknown

q = charge of proton = 1.6 x 10⁻¹⁹ C

m = mass of the proton = 1.67 x 10⁻²⁷kg

Substitute the values of m, q, B and r into equation (ii) above to get;

v = $\frac{1.6 * 10^{-19} * 0.3 * 0.2} {1.67*10^{-27} }$

Solving for v gives:

v = 5.75 x 10⁶ m/s

Therefore, the velocity of the proton is 5.75 x 10⁶ m/s

4 0

3 years ago