Answer:
The frequency of the tuning is 1.065 kHz
Explanation:
Given that,
Length of tube = 40 cm
We need to calculate the difference between each of the lengths
Using formula for length



For an open-open tube,
We need to calculate the fundamental wavelength
Using formula of wavelength

Put the value into the formula


We need to calculate the frequency of the tuning
Using formula of frequency

Put the value into the formula



Hence, The frequency of the tuning is 1.065 kHz
Much of the precipitation in large bodies of water occurs at the surface. The ocean loses about 37000 km cubed considering evaporation and precipitation.
<span>The moon's orbit around the Earth will advance in one day:
1°
13° correct answer
27°
29°</span><span />
Answer:
It is a instrument used to measure the distance traveled by a vehicle.
Explanation:
This is what it looks like ↓
Responder:
<h2>
0.7Hertz
</h2>
Explicación:
Usando la fórmula para calcular la velocidad de onda que se expresa como se muestra.
Velocidad de una onda = frecuencia * longitud de onda
v = fλ
Dada la velocidad de onda = 14 m / sy longitud de onda = 20 metros
frecuencia f = v / λ
f = 14/20
f = 0.7Hertz
La frecuencia de la onda es de 0.7 Hertz.