The final speed of the toy car at the end of the given time period is 3.58 m/s.
The given parameters;
- distance traveled by the car, s = 1.2 m
- time of motion of the car, t = 0.67 s
- initial velocity of the car, u = 0
The acceleration of the car is calculated as;

The final velocity of the toy car is calculated as;

Thus, the final speed of the toy car at the end of the given time period is 3.58 m/s.
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Answer:
Explanation:
Speed of an object is defined as the ratio of the distance covered by the object to the time taken to cover that distance.
Let
be the speed of the object.
Let
be the distance travelled by the object.
Let
be the time taken by the object.
So,
s=
So,the speed of the car is 
20N•m or 20J. Work is equal to force•distance, and 5N•4m is 20N•m, or J
Momentum = mass*velocity(or speed)
241.5 kg*m/s = 115 kg * v
v = 241.5 kg*m/s / 115 kg = 2.10 m/s
Use the definition of acceleration:
Acceleration = (change of velocity) divided by (time for the change)
The graph says:
Change of velocity = -6 m/s
Time for the change = 3 sec
So Acceleration = (-6m/s) / (3 s)
That's -6/3 m/s•s
or
-2 m/s^2