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algol [13]
2 years ago
14

Has anyone done this???i need the last questions for 1 and 2

Physics
1 answer:
Helen [10]2 years ago
8 0

Answer:

no i haven't done it

Explanation:

clean yo computer tho

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A student is transmitting sound waves through various materials. Through which metal in the table will the sound waves travel th
MariettaO [177]

Answer:

Aluminum

Explanation:

promise

give  me brainlest plleaseee

5 0
2 years ago
Read 2 more answers
Mary Sue is making caramel ice cream. In the first part of the process, she combines a cup of sugar and a cup of water in a sauc
timurjin [86]
<span>D. sugar changes from white to a light amber color We're looking for a chemical change. So let's examine the options and see what happening with them. A. adding cream and milk to the mixture She's just making a mixture here. No unexpected reactions or changes happen as she adds the cream and milk. So this is the wrong answer. B. mixing the sugar with water Dissolving the sugar in water. Once again, nothing unusual happens and if she were to evaporate the water, she'd be left with the original sugar. So this is the wrong answer. C. melting the sugar Just starting a simple phase change. Once again, no the right answer. D. sugar changes from white to a light amber color She's melted the sugar and has a clear fluid. As she continued to heat this fluid, it suddenly turns light amber. She has made a permanent change to the substance that she can't undo by simply physical means. She has converted part of the sugar into caramel. So a chemical change has happened here.</span>
7 0
3 years ago
Suppose you are standing on top of a hemisphere of radius r and you kick a soccer ball horizontally such that it has velocity v.
Ksivusya [100]

|v| =\sqrt{ G \cdot M / r}, where

  • M the mass of the planet, and
  • G the universal gravitation constant.

Explanation:

Minimizing the initial velocity of the soccer ball would minimize the amount of mechanical energy it has. It shall maintain a minimal gravitational potential possible at all time. It should therefore stay to the ground as close as possible. An elliptical trajectory would thus be unfavorable; the ball shall maintain a uniform circular motion as it orbits the planet.

<em>Equation 1</em>  (see below) relates net force the object experiences, \Sigma F to its orbit velocity v and its mass m required for it to stay in orbit :

\Sigma F = m \cdot v^{2} / r <em>(equation 1)</em>

The soccer ball shall experiences a combination of gravitational pull and air resistance (if any) as it orbits the planet. Assuming negligible air resistance, the net force \Sigma F acting on the soccer ball shall equal to its weight, W = m \cdot g where g the gravitational acceleration constant. Thus

\Sigma F = W = m \cdot g <em>(equation 2)</em>

Substitute equation 2 to the left hand side of <em>equation 1</em> and solve for v; note how the mass of the soccer ball, m, cancels out:

m \cdot g = \Sigma F = m \cdot v^{2} / r \\ v^{2} = g \cdot r \\ |v| = \sqrt{g \cdot r} \; (|v| \ge 0) <em>(equation 3)</em>

<em>Equation 4 </em> gives the value of gravitational acceleration, g, a point of negligible mass experiences at a distance r from a planet of mass M (assuming no other stellar object were present)

g = G \cdot M/ r^{2} <em>(equation 4)</em>

where the universal gravitation <em>constant</em> G = 6.67408 \times 10^{-11} \cdot \text{m}^{3} \cdot \text{kg}^{-1} \cdot \text{s}^{-2}

Thus

\begin{array}{lll}|v| &=& \sqrt{g \cdot r}\\ & =&\sqrt{ G \cdot M / r}\end{array}

3 0
3 years ago
According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle conn
suter [353]

This question is incomplete, the complete question is;

According to information found in an old hydraulics book, the energy loss per unit weight of fluid flowing through a nozzle connected to a hose can be estimated by the formula; h= (0.04 to 0.09)(D/d)⁴V²/2g

where h is the energy loss per unit weight, D the hose diameter, d the nozzle tip diameter, V the fluid velocity in the hose, and g the acceleration of gravity.

Do you think this equation is valid in any system of units

Answer:

YES, the equation is a general equation that is valid in any system of units

Explanation:

Given the data in the question;

h = (0.04 to 0.09)(D/d)⁴ × \frac{V^{2} }{2g}

so

[ N.m/N ] = (0.04 to 0.09) ( m/m)² × (m²/s²)1/2 × (s²/m)

[ N.L/N ] = (0.04 to 0.09) ( L⁴/L⁴) × (L²/T²)1/2 × (T²/L)

∴ [ L ] = (0.04 to 0.09) [L]

So as each term in the equation must have the same dimensions, the constant term (0.04 to 0.09) must be without dimension.

Therefore, YES, the equation is a general equation that is valid in any system of units

5 0
2 years ago
Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo
faltersainse [42]

Answer:

Length of pipe = 0.057 meter

Explanation:

Speed of a transverse wave on a string

v = \sqrt{\frac{F}{\mu} }

where F is the tension in string and \mu is the mass per unit length

Thus,

\mu = \frac{m}{L}

Substituting the given values we get -

\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}

Speed of a transverse wave on a string

v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}

For third harmonic wave , frequency is equal to

f = \frac{nv}{2L}

Substituting the given values, we get -

f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08

Length of pipe

L = \frac{nv}{4 f}

Substituting the given values we get

n = 1 for first harmonic wave

L = \frac{344* 1}{4*1502.08} \\L = 0.057

Length of pipe = 0.057 meter

5 0
3 years ago
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