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Gnoma [55]
4 years ago
9

Metals experience plastic deformation when _____.

Physics
1 answer:
SOVA2 [1]4 years ago
3 0
THE FORCE IS REMOVED BUT THE BODY DOES NOT RETURN TO ITS' ORIGINAL SHAPE (ALSO CALLED PERMANENT DEFORMATION)
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Spheres are not perfect in space. But <> is in the cause of their shape. ​
MariettaO [177]

Answer:

\boxed {  \tt{gravitational \: pull(force)}}

8 0
3 years ago
a pennyfarthing is a style of a bicycle with a very large front wheel and a small real wheel, the cyclist who sit high above and
s344n2d4d5 [400]

Answer:

In one rotation, the large wheel turns 4m.

Explanation:

The given values are:

Input distance,

= 0.64 m

Mechanical advantage,

= 0.16

As we know,

⇒ Out. \ Distance = \frac{Inp. \ distance}{Mechanical \ advantage}

On putting the values, we get

⇒                         =\frac{0.64}{0.16}

⇒                         =4 \ m

4 0
3 years ago
According to Newton, there were two things needed for an object to fall around or orbit the earth. Label the diagram below with
iVinArrow [24]

Centripetal force and centrifugal force


4 0
3 years ago
The final stages of a star's life depend on its mas. true or false?​
Diano4ka-milaya [45]

Answer:

TRUE

Explanation:

Low mass stars last lots longer.

5 0
3 years ago
A cheetah can run at a maximum speed 103 km/h and a gazelle can run at a maximum speed of 76.5 km/h. If both animals are running
Katena32 [7]

Answer:

1

 t_a  =  13.49 \  s

2

 The distance is   D = 55.2 \  m    

Explanation:

From the question we are told that

   The maximum speed of the cheetah is  v =  103 \  km/h =  28.61 \  m/s

    The maximum of  gazelle is  u =  76.5 \  km/h =  21.25 \  m/s

     The distance ahead is d =  99.3 \  m

Let  t_a denote the time which the cheetah catches the gazelle

Gnerally the equation representing the distance the cheetah needs to move in order to catch the gazelle is

           v* t_a = d +  u* t_a

=>          28.61 t_a = 99.3 +  21.25t_a

=>          7.36 t_a = 99.3

=>         t_a  =  13.49 \  s

Now at t =  7.5 s  

             7.5 v = D+  7.5u

=>          28.61 * 7.5  = D +  21.25* 7.5

=>          7.36 *  7.5 =D

=>         D = 55.2 \  m        

Hence the for the gazelle to escape the cheetah it must be 55.2 m

5 0
3 years ago
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