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2 years ago

Pls help i really did it plssssssssss

Mathematics

2 answers:

Montano1993 [528]2 years ago

7 0

Hi!

Given:

$(8x+14) + (9x-5)$

As we are adding the two groups, we can safely take them out of parentheses, as none of the signs will change:

$8x+14+9x-5$

Now, we can rearrange them to make it easier, placing like terms next to each other:

$8x+9x+14-5$

Now, add like terms:

$17x+9$

Therefore, your answer is D.

Bess [88]2 years ago

5 0

Answer:

Step-by-step explanation:

You can combine like terms meaning (8x+14)+ (9x-5) is 17x+9

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3 years ago

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After being treated with chemotherapy, the radius of the tumor decreased by 23%. What is the corresponding percentage decrease i

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Answer:

The volume of the tumor experimented a decrease of 54.34 percent.

Step-by-step explanation:

Let suppose that tumor has an spherical geometry, whose volume ( $V$ ) is calculated by:

$V = \frac{4\pi}{3}\cdot R^{3}$

Where $R$ is the radius of the tumor.

The percentage decrease in the volume of the tumor ( $\%V$ ) is expressed by:

$\%V = \frac{\Delta V}{V_{o}} \times 100\,\%$

Where:

$\Delta V$ - Absolute decrease in the volume of the tumor.

$V_{o}$ - Initial volume of the tumor.

The absolute decrease in the volume of the tumor is:

$\Delta V = V_{o}-V_{f}$

$\Delta V = \frac{4\pi}{3}\cdot (R_{f}^{3}-R_{o}^{3})$

The percentage decrease is finally simplified:

$\%V = \left[1-\left(\frac{R_{f}}{R_{o}}\right)^{3} \right]\times 100\,\%$

Given that $R_{o} = R$ and $R_{f} = 0.77\cdot R$ , the percentage decrease in the volume of tumor is:

$\%V = \left[1-\left(\frac{0.77\cdot R}{R}\right)^{3} \right]\times 100\,\%$

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The volume of the tumor experimented a decrease of 54.34 percent.

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3 years ago

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3 years ago

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Answer:

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Since 3/4 of 100 is 75, we have to divide 450 by three.

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Hope this helps :)