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borishaifa [10]
2 years ago
9

Each degree on the Kelvin scale equals how many degrees on the Celius scale

Physics
1 answer:
Mamont248 [21]2 years ago
8 0

Answer:

0° C = 273.15 K

0 K = - 273.15° C

Explanation:

<em>Hello there!</em>

The Kelvin temperature scale refers to the absolute temperature scale. The division in the Kelvin scale is equal to a degree on the Celsius scale only it's difference is zero

The Celsius scale of zero (0°C) is the freezing point.

0 K is Absolute Zero.

•°• 0 K = - 273.15° C

0° C = 273.15 K

Furthermore, this is what I would like you to know about this scales;

<em>The </em><em>Kelvin </em><em>scale </em><em>is </em><em>used </em><em>for</em><em> </em><em>very </em><em>low </em><em>or </em><em>very </em><em>high </em><em>temperatures</em><em> </em><em>where </em><em>water </em><em>is </em><em>not </em><em>involved</em><em>.</em>

<em>Note:</em><em> </em>

<em>The </em><em>boiling</em><em> point</em><em> of</em><em> water</em><em> is</em><em> </em><em>1</em><em>0</em><em>0</em><em>°</em><em>C</em><em>.</em>

I hope this helps you to understand more on this scales. Have a nice studies.

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4 0
3 years ago
Read 2 more answers
 A car whose initial speed is 30 m/s slows uniformly to 10 m/s in 5 seconds. Determine the acceleration of the car. Sketch a gra
Anton [14]
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\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{10-30}{5}

\\ \sf\longmapsto Acceleration=\dfrac{-20}{5}

\\ \sf\longmapsto Acceleration=-4m/s^2

Now

For the second question

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\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto s=30(3)+\dfrac{1}{2}(-4)(3)^2

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You are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. Whic
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Answer:

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e. increasing the current in the solenoid

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6 0
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Answer:

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