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marusya05 [52]
3 years ago
5

. The naturally occurring charge on the ground on a fine day out in the open country is –1.00nC/m2 . (a) What is the electric fi

eld relative to ground at a height of 3.00 m? (b) Calculate the electric potential at this height. (c) Sketch electric field and equipotential lines for this scenario.
Physics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

a) -113 N/C

b) -423.71 V

Explanation:

The Step by step explanation and solution has been attached in the attachment section.

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Electricity is distributed from electrical substations to neighborhoods at 13000 V. This is a 60 Hz oscillating (AC) voltage. Ne
Levart [38]

Answer:

the number of turns in the primary coil is 13000

Explanation:

Given the data in the question;

V₁ = 13000 V

V₂ = 120 V

N₁ = ?

N₂ = 120 turns

the relation between the voltages and the number of turns in the primary and secondary coils can be expressed as;

V₁/V₂ = N₁/N₂

V₁N₂ = V₂N₁

N₁ = V₁N₂ / V₂

so we substitute

N₁ = (13000 V × 120 turns) / 120 V

N₁ = 1560000 V-turns / 120 V

N₁ = 13000 turns

Therefore, the number of turns in the primary coil is 13000

8 0
2 years ago
An insulated lunch bag keeps food warm by
Hatshy [7]
I believe the answer is D
4 0
3 years ago
Read 2 more answers
**URGENT PLEASE HELP**
nalin [4]

Answer:

This depends on what angle they are approaching each other before they collided.The two simple cases are if they are running in the same direction or opposite direction from each other. For either case, use the conservation of momentum equation to solve: M_total*V_result = M1*V1 + M2*V2

Explanation:

Here are two possible solutions.

Head-on collision: M1=78, V1=8.5, M2=72, V2=-7.5 (that's negative because he's running the other way), M_total = 78+72 = 150, so V_result = (78*8.5 - 72*7.5)/150 = 0.82 m/s. Sanity check, they weigh about the same and so most of their velocity should cancel out.

Running the same way: change the sign of V2 to positive so V_result = (78*8.5 + 72*7.5)/150 = 8.02 m/s. Sanity check, they weigh about the same and the resultant speed is between the two starting velocities.

<em>hope it helps:)</em>

7 0
3 years ago
Read 2 more answers
An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude
blagie [28]

Answer:

(A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

Explanation:

Given that,

Initial angular velocity = 0.200 rev/s

Angular acceleration = 0.883 rev/s²

Diameter = 0.760 m

Time = 0.204 s

(A). We need to calculate the angular velocity of fan

Using equation of angular motion

\omega_{f}=\omega_{i}+\alpha t

Put the value into the formula

\omega_{f}=0.200+0.883\times0.204

\omega_{f}=0.380\ rev/s

(B). We need to calculate the number of revolution

Using formula of angular displacement

\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2

\theta=0.059\ rad

(C). We need to calculate the tangential speed of the blade

Using formula of speed

v=\dfrac{d}{2}\omega_{f}

Put the value into the formula

v=\dfrac{0.760}{2}\times0.380\times2\pi

v=0.907\ m/s

(D). We need to calculate the tangential acceleration of the blade

Using formula of tangential acceleration

a_{t}=\alpha r

Put the value into the formula

a_{t}=0.883\times0.38\times2\pi

a_{t}=2.10\ m/s^2

Hence, (A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

3 0
3 years ago
James Joule (after whom the unit of energy is named) claimed that the water at the bottom of Niagara Falls should be warmer than
Y_Kistochka [10]

The complete question is;

James Joule (after whom the unit of energy is named) claimed that the water at the bottom of Niagara Falls should be warmer than the water at the top, 51 m above the bottom. He reasoned that the falling water would transform its gravitational potential energy at the top into thermal energy at the bottom, where turbulence brings the water almost to a halt. If this transformation is the only process occurring, how much warmer will the water at the bottom be?

Answer:

Water becomes warmer by a temperature of ΔT = 0.119 K

Explanation:

If we assume that gravitational kinetic energy will be converyrf into thermal enrgy, we will have;

Q = U

So, m•c_w•ΔT = mgh

Where;

c_w is specific heat capacity of water with a value of 4184 J/Kg.K

ΔT is change in temperature indicating how warmer the water will be. Thus making ΔT the subject, we have;

ΔT = gh/c_w

So, ΔT = 9.8 x 51/4184 = 0.119 K

4 0
3 years ago
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