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marusya05 [52]
3 years ago
5

. The naturally occurring charge on the ground on a fine day out in the open country is –1.00nC/m2 . (a) What is the electric fi

eld relative to ground at a height of 3.00 m? (b) Calculate the electric potential at this height. (c) Sketch electric field and equipotential lines for this scenario.
Physics
1 answer:
JulijaS [17]3 years ago
4 0

Answer:

a) -113 N/C

b) -423.71 V

Explanation:

The Step by step explanation and solution has been attached in the attachment section.

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If a car accelerates uniformly from rest to 15 meters
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Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

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v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

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Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

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The answer is 'more' as more mass can exert more pressure

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An Olympic runner completes the 200-meter sprint in 23 seconds. What is the runner’s average speed? (Round your answer to the ne
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Answer:

The right approach is Option b (the force..................exert on you).

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The other options given are not connected to the situation described. So, the solution here was the right one.

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