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kondaur [170]
4 years ago
7

You are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. Whic

h of the following increases the energy density? (Select all that apply.)
a. Increasing only the length of the solenold while keeping the turns per unit lengh flxed
b. increasing the number of turns per unit length on the solenold
c. increasing the cross-sectional area of the solenoid
d. none of these
e. increasing the current in the solenoid
Physics
1 answer:
Alinara [238K]4 years ago
5 0

Answer:

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

Explanation:

As we know that energy density depends on the strength of the magnetic field. The magnetic field strength depends on the no of turns of the solenoid and the current passing through it. The greater the number of turns per unit length, greater the current passing through it, more stronger the magnetic field is. As

B = μ₀nI

n = no of turns

I = current through the wire

So the right options are

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

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A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan
Nesterboy [21]

Answer:

Compression distance: d \approx 0.102\,m

Explanation:

According to this statement, we know that system is non-conservative due to the rough patch. By Principle of Energy Conservation and Work-Energy Theorem, we have the following expression that represents the system having a translational kinetic energy (K), in joules, at the expense of elastic potential energy (U), in joules, and overcoming work losses due to friction (W_{l}), in joules:

K + W_{l} = U (1)

By definitions of translational kinetic and elastic potential energies and work losses due to friction, we expand the equation described above:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2} (2)

Where:

m - Mass of the block, in kilograms.

v - Final velocity of the block, in meters per second.

\mu - KInetic coefficient of friction, no unit.

g - Gravitational acceleration, in meters per square second.

s - Width of the rough patch, in meters.

k - Spring constant, in newtons per meter.

d - Compression distance, in meters.

If we know that m = 1.2\,kg, v = 2.3\,\frac{m}{s}, \mu = 0.44, g = 9.807\,\frac{m}{s^{2}}, s = 0.05\,m and k = 730\,\frac{N}{m}, then the compression distance of the spring is:

\frac{1}{2}\cdot m \cdot v^{2} +\mu\cdot m\cdot g \cdot s = \frac{1}{2}  \cdot k \cdot d^{2}

m\cdot v^{2} + 2\cdot m\cdot g \cdot s = k\cdot d^{2}

d = \sqrt{\frac{m\cdot (v^{2}+2\cdot g\cdot s)}{k} }

d \approx 0.102\,m

4 0
3 years ago
NEED TODAY
lisabon 2012 [21]

Answer:

No, projectile launched at 20° landed first.

Explanation:

70° projectile had a vertical velocity of v*sin(70), which is significantly bigger than v*sin(20). Since v=vx+at, we can see that Vyi*sin(20)-gt < Vyi*sin(70)-gt

solve for t, you can check that by substituting velocity for any number.

3 0
2 years ago
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You plan to take your hair blower to europe, where the electrical outlets put out 240 v instead of the 120 v seen in the united
Dmitrij [34]
P = U × I
I = P / U = 1600W / 120V = 13.4A
P = 240V × 13.4A = 3216W

If your hair blower isnt rated for 220- 230V(this is the voltage in EU) you are most likely going to burn it.
8 0
3 years ago
Một nhà máy điện hơi nước nhận nhiệt từ một lò nung với tốc độ 280(gj/h) . Tổn thất nhiệt cho không khí xung quanh khi nó đi qua
weeeeeb [17]

what is languange?????

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3 years ago
When a current of 5 amperes is run through the coiled heating element of a stove, the resistance of the element is 80 ohms. What
dangina [55]
16 I think lol !!!!!!
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