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galina1969 [7]
2 years ago
10

Please help

Mathematics
1 answer:
zheka24 [161]2 years ago
3 0
The answer is C

O,p,m,q,n
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Find the coordinates of the points of intersection of the parabola y=x^2+3x-4 and the line y=2x+2
lana [24]
You can set the y values equal to each other and solve the system:

x^2+3x-4=2x+2
x^2+x-6=0
(x+3)(x-2)=0
x=-3,2

So, these are the x values of the intersection. To get the y values, you can just plug them back into either formula:

y=2(-3)+2
y=-4

y2(2)+2
y=6

So the coordinates are (-3,-4) and 2,6).
6 0
3 years ago
Ranking correct answer brainliest !
icang [17]

Answer:

a linear pair

Step-by-step explanation:

3 0
2 years ago
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What is the side length of the square shown Below. Please SHOW your work.
barxatty [35]

Answer:

side length = (x+11)

Step-by-step explanation:

area = x^2+22x+121

side length = sq rt (x^2+22x+121)

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3 years ago
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A classic counting problem is to determine the number of different ways that the letters of millennium can be arranged. Find tha
Eddi Din [679]

Answer:

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of letters of the word "millennium" = 10

Letters repeated:

m = 2 times

i = 2 times

l = 2 times

n = 2 times

2. The number of different ways that the letters of millennium can be arranged is:

We will use the n! or factorial formula, this way:

10!/2! * 2! * 2! * 2!

(10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1)/(2 * 1) * (2 * 1) * (2 * 1) * (2 *1)

3'628,800/2*2*2*2 = 3'628,800/16 = 226,800

<u>The correct answer is that the number of different ways that the letters of the word "millennium" can be arranged is 226,800</u>

7 0
3 years ago
I NEED HELP WITH THIS ASAP
grin007 [14]
hopefully someone helps u with this tho sorry
3 0
2 years ago
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