Answer:
Mass = 26.50 g
Explanation:
Given data:
Mass of sodium carbonate = ?
Molarity of solution = 0.25 M
Volume of solution = 1.00 L
Solution:
Molarity = number of moles / volume in litter
0.25 M = number of moles / 1.00 L
Number of moles = 0.25 M × 1.00 L
Number of moles = 0.25 mol
Mass:
Mass = number of moles × molar mass
Mass = 0.25 mol × 106 g/mol
Mass = 26.50 g
The relative atomic mass of Boron in trimethyl borate [(CH3O)3B] is; 10.8
<h3>Isotopes and Relative abundance</h3>
According to the question;
- Since, ¹¹B is 4 times more abundant than ¹⁰B;
The relative abundance of Boron in the spectrum is;
Relative atomic mass = (80% of 11) + (20% of 10)
Hence, the relative atomic mass of Boron in trimethyl borate [(CH3O)3B] is; 10.8
Read more on Isotopes;
brainly.com/question/14220416
Answer:
n = 3.0 moles
V = 60.0 L
T = 400 K
From PV = nRT, you can find P
P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L
P = 1.642 atm = 1.6 atm (to 2 significant figures)
Explanation:
In earths surface or the bottom of the Ocean
