Answer:
All of the above processes have a ΔS < 0.
Explanation:
ΔS represents change in entropy of a system. Entropy refers to the degree of disorderliness of a system.
The question requests us to identify the process that has a negative change of entropy.
carbon dioxide(g) → carbon dioxide(s)
There is a change in state from gas to solid. Solid particles are more ordered than gas particles so this is a negative change in entropy.
water freezes
There is a change in state from liquid to solid. Solid particles are more ordered than liquid particles so this is a negative change in entropy.
propanol (g, at 555 K) → propanol (g, at 400 K)
Temperature is directly proportional to entropy, this means higher temperature leads t higher entropy.
This reaction highlights a drop in temperature which means a negative change in entropy.
methyl alcohol condenses
Condensation is the change in state from gas to liquid. Liquid particles are more ordered than gas particles so this is a negative change in entropy.
Answer:
Any binary molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
Explanation:
Going down in a group increases the atomic radius and a greater atomic radius implyes greater ionic radius.
When ionization takes place in these compounds they yelds protons (hidrogen ion) and an lewis base (anion). The greater the ionic radius the greater its stability, thus the periodic tendency is increaing the acidity of binary hidrogen compounds when going down a group. On the other hand going up a group decreases acidity, so any molecular compound of hydrogen and a Group 6A element above Selenium will be less acidic, so water and dihydrogen sulfide are less acidic in aqueous solution than hydrogen selenide.
The answer is: [D]: " AgCl " .
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Explanation:
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Given the chemical reaction:
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NaCl (aq) + AgNO₃ (aq) <span>→ </span> NaNO₃ (aq) + AgCl (s) ;
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The "reactants" , which are on the "left-hand side" of the chemical equation, are:
"NaCl" (in aqueous solution); and "AgNO₃" (in aqueous solution).
The "products", which are on the "right-hand side" of the chemical equation, are:
"NaNO₃" (in aqueous solution); and: "AgCl" (as a "solid").
The "AgCl" (as a "product"—which is a "solid"—would be the "precipitate" ;
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→ which is: Answer choice: [D]: " AgCl " .
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