<h2>Answer:</h2><h3>Part 1. </h3>
Option B is correct option.
The half-reaction 2MnO2 + H2O + 2e- Mn2O3 is missing OH- ions.
Explanation:
Full equation:
2MnO2 + H2O + 2e- → Mn2O3 + 2OH-
<h3>Part 2:</h3>
The option B which is Mg is stronger reducing agent than Ag is correct option.
Explanation:
Equation:
Mg(s) + 2Ag+ (aq) → Mg2+ (aq) + 2Ag(s)
According to equation Mg converts to Mg+2 which means it gives to electron to reduce Ag. So it act as an reducing agent.
<h3>Part 3:</h3>
The correct option is B. Which is 5, 1, 8, 5, 1, 4.
Explanation:
Full equation :
5 Fe²⁺ (aq) + MnO₄⁻ (aq) + 8 H⁺ (aq) --> 5 Fe³⁺ (aq) + Mn²⁺ (aq) + 4 H₂O (l)
<h3 />
The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL
<u>Given data :</u>
Concentration of siilver nitrate ( M₁ ) = 6.0 M
volume of solution ( V₁ ) = 500 mL
Conc of solution ( M₂ )= 1.2 M
<h3>Determine the amount of water that must be added</h3>
we will apply the equation below
M₁V₁ = M₂V₂ ---- ( 1 )
where : V₂ = V₁ + water added ---- ( 2 )
V₂ ( Final volume ) = ( M₁V₁ ) / M₂
= ( 6 * 500 ) / 1.2
= 2500 mL
Back to eqaution ( 2 )
2500 mL = 500 mL + added water
therefore ; added water = 2500 - 500
= 2000 mL
Hence we can conclude that The amount of water that must be added to 6.0 M silver nitrate to make 500mL of 1.2 M solution is : 2000 mL.
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Answer:
The pH of the solution is 4.60.
Explanation:
The pH gives us an idea of the acidity or basicity of a solution. More precisely, it indicates the concentration of H30 + ions present in said solution. The pH scale ranges from 0 to 14: from 0 to 7 corresponds to acid solutions, 7 neutral solutions and between 7 and 14 basic solutions. It is calculated as:
pH = -log (H30 +)
pH= -log (2,5 x 10-5)
<em>pH=4.60</em>
