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erma4kov [3.2K]
3 years ago
9

A student performed an investigation at sea level. First she placed 400 mL of water in four different containers. Then she place

d the containers on hot plates with four different temperature settings, as shown in the table.

Chemistry
1 answer:
Feliz [49]3 years ago
4 0

Answer:

  C. The boiling point of water

Explanation:

We assume your question is the one attached.

Obviously, the shape of the (liquid) water is a function of the container it is in, as it is for any liquid or gas.

The rate of evaporation will depend on the temperature and on the surface area. The different containers are different in both ways, so evaporation is not a constant.

The boiling point is a physical property of the water, so will be the same across all containers.

The amount of steam released is related to the rate of evaporation. It will not be a constant across the different containers.

__

The appropriate choice is ...

  The boiling point of water

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What is the concentration of H+ in 0.0025 M HClO4? What is the pH of the solution? What is the OH− concentration in the solution
alexandr402 [8]

Answer:

A. The concentration of H+ is 0.0025 M

B. The pH is 2.6

C. The concentration of OH- is 3.98x10^-12 M

Explanation:

We'll begin by writing the balanced

dissociation equation of HClO4. This is illustrated below:

HClO4 —> H+ + ClO4-

A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:

From the balanced equation above,

1 mole of HClO4 produced 1 mole of H+.

Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.

The concentration of H+ is 0.0025 M

B. Determination of the pH.

The pH of the solution can be obtained as follow:

The concentration of H+, [H+]

= 0.0025 M

pH =?

pH = - log [H+]

pH = - log 0.0025

pH = 2.6

C. Determination of the concentration of OH-

To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:

pH + pOH = 14

pH = 2.6

pOH =?

pH + pOH = 14

2.6 + pOH = 14

Collect like terms

pOH = 14 - 2.6

pOH = 11.4

Now, we can calculate the concentration of the OH- as follow:

pOH = - Log [OH-]

pOH = 11.4

11.4 = - Log [OH-]

- 11.4 = log [OH-]

[OH-] = anti log (- 11.4)

[OH-] = 3.98x10^-12 M

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MnO2 + 4HCl reacts to form MnCl2 + CL2 + 2H2O If .86 mol of MnO2 and 48.2 g of HCl react, which reactant is the limiting reagent
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HCl:
<span>
m=48,2g
M=36,5g/mol

n = m/M = 48,2g / 36,5g/mol = 1,32mol

1mol          : 4mol
MnO</span>₂        + 4HCl ⇒ MnCl₂ + Cl₂ + 2H₂O
0,86mol     :  1,32mol
                     limiting reagent 
0,33 will react

HCl is limiting reagent.
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Write an ionic equation of hydrogen peroxide reacting with sodium sulphite​
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Answer:

Na2SO3 + H2O2 = Na2SO4 + H2O

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