Answer:
Total change in energy = 31 KJ.
Explanation:
Mass m=25 kg
Height h = 1 m
Initial velocity = 0
Final velocity = 50 m/s
Energy at initial condition



Energy at final condition


So the change in energy = 31250 -250 J
The total change in energy = 31000 J
Explanation:
The tear test determines the force required by a material to undergo complete failure when there is already a crack or tear present in it.
With this test we understand a material's resistance to failure when there is already a crack present.
The material which already has a crack is placed in a tensile testing or universal test machine. So, both sides of the material along the crack are pulled until material failure takes place.
Answer:
The answer is "15 N".
Explanation:
Please find the complete question in the attached file.
In frame B:
For just slipping:


Answer: c.An accumulator is not used in a system with a receiver/dryer
Explanation:
In a refrigeration system, a condenser is used to transfer heat and this occurs from the refrigerant to the air or water.
Then, the refrigerant then condenses to liquid when the hear has been transferred.
We should note that the condenser is normally mounted in front of the radiator. The receiver/dryer is a storage tank for the liquid refrigerant from the condenser.
The statement that an accumulator is not used in a system with a receiver/dryer is not true. This is because, the accumulator gives protection to the compressor which helps to prevent the failure of the compressor.
Therefore, the answer is C.
Answer:
When water is surrounding T_s = 34.17 degree C
When air surrounding T_S = 1434.7 degree C
from above calculation we can conclude that air is less effective than water as heat transfer agent
Explanation:
Given data:
length = 300 mm
Outer diameter = 30 mm
Dissipated energy = 2 kw = 2000 w
Heat transfer coefficient IN WATER = 5000 W/m^2 K
Heat transfer coefficient in air = 50 W/m^2 K
we know that 
From newton law of coding we have

is surface temp.
T - temperature at surrounding
![P = hA(T_s - T_{\infity})[tex]\frac{P}{\pi hDL} = (T_s - T_{\infity})](https://tex.z-dn.net/?f=P%20%3D%20hA%28T_s%20-%20%20T_%7B%5Cinfity%7D%29%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cfrac%7BP%7D%7B%5Cpi%20hDL%7D%20%3D%20%20%28T_s%20-%20%20T_%7B%5Cinfity%7D%29)
solving for[/tex] T_s [/tex] w have



When air is surrounding we have



from above calculation we can conclude that air is less effective than water as heat transfer agent