1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yuradex [85]
3 years ago
13

A 150-lbm astronaut took his bathroom scale (a spring scale) and a beam scale (compares masses) to the moon where the local grav

ity is g = 5.48 ft/s^2. Determine how much he will weigh (a) on the spring scale and (b) on the beam scale.The acceleration of high-speed aircraft is sometimes expressed in g’s (in multiples of the standard acceleration of gravity). Determine the net upward force, in N, that a 90-kg man would experience in an aircraft whose acceleration is 6 g’s.
Engineering
1 answer:
kozerog [31]3 years ago
3 0

Answer:

a)Wt =25.68 lbf

b)Wt = 150 lbf

F= 899.59 N

Explanation:

Given that

g = 5.48 ft/s^2.

m= 150 lbm

a)

Weight on the spring scale(Wt) = m g

We know that

1\ lbf=32.17 \ lmb.ft/s^2

Wt = 150 x 5.48/32 lbf

Wt =25.68 lbf

b)

On the beam scale

This is scale which does not affects by gravitational acceleration.So the wight on the beam scale will be 150 lbf.

Wt = 150 lbf

If the plane is moving upward with acceleration 6 g's then the for F

F = m a

We know that

1\ ft/s^2= 0.304\ m/s^2

5.48\ ft/s^2= 1.66\ m/s^2

a=6 g's

a=9.99\ m/s^2

So

F = 90 x 9.99 N

F= 899.59 N

You might be interested in
Air enters a constant-area combustion chamber at a pressure of 101 kPa and a temperature of 70°C with a velocity of 130 m/s. By
Norma-Jean [14]

Answer:

451 kj/kg

Explanation:

Velocity = 139m/s

Temperature = 70⁰C

T = 343K

M1 = v/√prt

= 130/√1.4x287x343

= 130/√137817.4

= 130/371.2

= 0.350

T1/To1 = 0.9760

From here we cross multiply and then make To1 the subject of the formula

To1 = T1/0.9760

To1 = 343/0.9760

To1 = 351.43

Then we go to the rayleigh table

At m = 0.35

To1/To* = 0.4389

To* = 351.43/0.4389

= 800k

M2 = 1

Maximum amount of heat

1.005(800-351.43)

= 450.8kj/kg

= 452kj/kg

8 0
3 years ago
From the following numbered list of characteristics, decide which pertain to (a) precipitation hardening, and which are displaye
tia_tia [17]

Answer:

(a) Precipitation hardening - 1, 2, 4

(b) Dispersion strengthening - 1, 3, 5

Explanation:

The correct options for each are shown as follows:

Precipitation hardening

From the first statement; Dislocation movement is limited by precipitated particles. This resulted in an expansion in hardness and rigidity. Precipitates particles are separated out from the framework after heat treatment.

The aging process occurs in the second statement; because it speaks volumes on how heated solutions are treated with alloys above raised elevated temperature. As such when aging increases, there exists a decrease in the hardness of the alloy.

Also, for the third option for precipitation hardening; This cycle includes the application of heat the alloy (amalgam) to a raised temperature, maintaining such temperature for an extended period of time. This temperature relies upon alloying components. e.g. Heating of steel underneath eutectic temperature. Subsequent to heating, the alloy is extinguished and immersed in water.

Dispersion strengthening

Here: The effect of hearting is not significant to the hardness of alloys hardening by the method in statement 3.

In statement 5: The process only involves the dispersion of particles and not the application of heat.

8 0
3 years ago
The distillation column in Figure 3 is set up for so-called boil-up (V) control. It has
11111nata11111 [884]

A distillation column is an essential item used in the distillation of liquid mixtures to separate the mixture into its component parts, or fractions, based on the differences in volatilities. Fractionating columns are used in small scale laboratory distillations as well as large scale industrial distillations.

3 0
3 years ago
Why the velocity potential Φ(x,y,z,t) exists only for irrotational flow
Black_prince [1.1K]

Answer:

\omega_y,\omega_x,\omega_Z  all are zero.

Explanation:

We know that if flow is possible then it will satisfy the below equation

\dfrac{\partial u}{\partial x}+\dfrac{\partial v}{\partial y}+\dfrac{\partial w}{\partial z}=0

Where u is the velocity of flow in the x-direction ,v is the velocity of flow in the y-direction and w is the velocity of flow in z-direction.

And velocity potential function \phi given as follows

 u=-\frac{\partial \phi }{\partial x},v=-\frac{\partial \phi }{\partial y},w=-\frac{\partial \phi }{\partial z}

Rotationality of fluid is given by \omega

\frac{\partial v}{\partial x}-\frac{\partial u}{\partial y}=\omega_Z

\frac{\partial v}{\partial z}-\frac{\partial w}{\partial y}=\omega_x

\frac{\partial w}{\partial x}-\frac{\partial u}{\partial z}=\omega_y

So now putting value in the above equations ,we will find

\omega =\frac{\partial \phi }{\partial x},u=\frac{\partial \phi }{\partial x},

\omega_y=\dfrac{\partial^2 \phi }{\partial z\partial x}-\dfrac{\partial^2 \phi }{\partial z\partial x}

So \omega_y=0

Like this all \omega_y,\omega_x,\omega_Z all are zero.

That is why  velocity potential flow is irroational flow.

5 0
4 years ago
Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact di
Ilya [14]

Answer:

Problem 1 (10 points) In the first homework you were instructed to design the mechanical components of an oscillating compact disc reader. Since you did such a good job in your design, the company decided to work with you in their latest Blue-ray readers, as well. However, this time the task is that once the user hits eject button, the motor that spins the disc slows down from 2000 rpm to 300 rpm and at 300 rpm a passive torsional spring-damper mechanism engages to decelerate and stop the disc. Here, your task is to design this spring-damper system such that the disc comes to rest without any oscillations. The rotational inertia of the disc (J) is 2.5 x 10-5kg m² and the torsional spring constant (k) is 5 × 10¬³NM. Calculate the critical damping coefficient cc for the system. choice of the damper, bear in mind that a good engineer stays at least a factor of In your 2 away from the danger zone (i.e., oscillations in this case). Use the Runge Kutta method to simulate the time dependent angular position of the disc, using the value of damping coefficient (c) that calculated. you Figure 1: Blue-ray disc and torsional spring-damper system.

5 0
3 years ago
Other questions:
  • Which option should the engineers focus on as they develop the train in the following scenario?
    12·1 answer
  • A subway car leaves station A; it gains speed at the rate of 4 ft/s^2 for of until it has reached and then at the rate 6 then th
    8·1 answer
  • What is the thermal efficiency of a gas power cycle using thermal energy reservoirs at 627°C and 60°C? The thermal efficiency is
    12·1 answer
  • Microchips found inside most electronic devices today are examples of what material A. Polymers B. Alloys C. Composites D. None
    10·2 answers
  • Type the correct answer in the box. Spell all words correctly.
    6·1 answer
  • Consider a normal shock wave in air. The upstream conditions are given by M1=3, p1 = 1 atm, and r1 = 1.23 kg/m3. Calculate the d
    15·1 answer
  • A rectangular channel 3-m-wide carries 12 m^3/s at a depth of 90cm. Is the flow subcritical or supercritical? For the same flowr
    15·1 answer
  • Do you play escape from tarkov if so do you want to play it with me​
    13·1 answer
  • Which of the following procedures best applies to assessing the embodied energy of a building?
    12·1 answer
  • Refrigerant 134a passes through a throttle valve as part of a refrigeration cycle. The fluid enters the valve as compressed liqu
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!