Answer:
a. 17 μC b. 14.45 J
Explanation:
Here is the complete question
A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.
a. What charge is stored in each capacitor?
b. How much energy is stored in each capacitor?
a. The charge Q stored in a capacitor is Q = CV where C = capacitance and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.
So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC
b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² = 1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J
Answer:
118.166 volt
Explanation:
We have given number of turns N =345
Sides of the rectangular coils is 12 cm =0.12 m
So area A =0.12×0.12=0.0144 
Magnetic field B =0.45 T
Angular speed =505 rpm
Speed in rad/sec 
The emf is given by
For maximum emf sinwt =1
So 
Answer
given,
angle with horizontal = 12°
constant speed with the slope = 1 m/s
Work on the skier to move 8 m = 900 J
a) Rope moved with constant speed
change in kinetic energy is equal to zero
work done by the force of the rope = 900 J
rate of force of the rope when skier move with
b) v = 1 m/s total time t = 8 s
Power =
=
= 112.5 W
c) v = 2 m/s total time t = 8/2 = 4 s
Power =
=
= 225 W
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