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3 years ago

15

Describe the relationship between the Law of Conservation of Matter and balancing equations.

2 answers:

Brilliant_brown [7]3 years ago

7 0

Detailed Explanation:

The Law of Conservation of Mass states that "In a chemical reaction, matter is neither created nor destroyed.".
We balance chemical equations in order to satisfy the Law of Conservation of Mass.
Balanced chemical equations show that mass is conserved in chemical reactions. In a balanced equation, there will be same number of each type of atom on both sides of the arrow.

Yuliya22 [10]3 years ago

3 0

Answer:

The mass of the products and reactants are the same on both sides of the equation.

The number of atoms of products and reactants are equal and hence it proves the law of conservation of mass.

.

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Whats the difference between work and power

Vika [28.1K]

The main relationship or difference between<span> the two is time. </span>Work<span> is the amount of energy necessary to move an object from one point to another. Imagine moving a table or seat from your living room to your dining room. On the other hand, </span>power<span> is the rate at which the energy is spent.</span>

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3 years ago

Read 2 more answers

Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an

Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

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4 years ago

You need to design a banked curve at the new circular Super 100 Raceway. The radius of the track is 800 m and cars typically tra

uysha [10]

Answer:

$33.1^{\circ}$

Explanation:

Let's start by writing the equations of the forces along the two directions:

- Vertical:

$N cos \theta = mg$

where

N is the normal reaction

$\theta$ is the angle between the road and the horizontal

(mg) is the weight of the car, with m being its mass and g the acceleration of gravity

- Horizontal:

$N sin\theta = m \frac{v^2}{r}$

where

v is the speed of the car

r is the radius of the turn

Dividing the 2nd equation by the 1st one, we get:

$tan \theta = \frac{v^2}{rg}$

In this problem:

$r = 800 m$ (radius of the turn)

$v=160 mi/h = 71.5 m/s$ is the speed

$g=9.8 m/s^2$

Substituting, we find:

$\theta= tan^{-1} (\frac{v^2}{rg})=tan^{-1}(\frac{(71.5)^2}{(800)(9.8)})=33.1^{\circ}$

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4 years ago

What is the charge on an object that has 1.09x10^13 excess electrons?

Nadya [2.5K]

Answer:

$-1.74\cdot 10^{-6} C$

Explanation:

The electron is the particle that rotates around the nucleus of the atom; it has a negative electric charge equal to :

$e=-1.6\cdot 10^{-19}C$

which is known as fundamental charge.

For an object containing N excess electrons, the total charge of the object is

$Q=Ne$

In this problem, the number of excess electrons in the object is:

$N=1.09\cdot 10^{13}$

Therefore, by plugging it the numbers, we can find the value of Q, the total charge of the object:

$Q=(1.09\cdot 10^{13})(-1.6\cdot 10^{-19})=-1.74\cdot 10^{-6} C$

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4 years ago

Two blocks, stacked one on top of the other, slide on a frictionless horizontal surface. The surface between the two blocks is r

devlian [24]

Answer:

$F_{net} = 31.88 N$

Explanation:

When top block is just or about to slide on the lower block then we can say that the frictional force on it will be maximum static friction

So we will have

$F_{net} = ma$

$F_s = ma$

$\mu_s mg = ma$

$a = \mu_s g$

$a = (0.50)(9.81)$

$a = 4.905 m/s^2$

now for the Net force on two blocks to move together

$F_{net} = (m_1 + m_2) a$

$F_{net} = (2.3 + 4.2)(4.905)$

$F_{net} = 31.88 N$

4 0

3 years ago