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Fudgin [204]
2 years ago
12

Calculate the Gibbs energy, entropy, and enthalpy of mixing when 1.00mol C6H14 (hexane) is mixed with 1.00mol C7H16 (heptane) at

298K. Treat the solution as ideal.
Chemistry
1 answer:
Norma-Jean [14]2 years ago
5 0

With Hexane of 1.00 ml and 1.00 ml of hectane at 298, the calculated

  • Gibbs energy = 3.43
  • Entropy = -3.43
  • Enthalpy = 0

<h3>How to solve for the Gibbs energy </h3>

C6H14 = C6H14/C6H14+C7H16

1mol/1mol+1mol = 1/2 = 0.5 mol

1+1 x 8.3145J x 298 x 0.5ln0.5 + 0.5ln0.5

= 4955.442 0.6932

= 3435J

convert to KJ

G mix = 3.43

The Gibbs energy is therefore  3.43KJ/mol

<h3>The entropy of the solution</h3>

-(1+1 x 8.3145J x 298 x 0.5ln0.5 + 0.5ln0.5)

S mix = -3.43 KJ/mol

3.43/298 = 11.5

The enthalpy of the solution

3.43-3.43 KJ/mol

H mix = 0

Read more on gibbs solution here: brainly.com/question/17310317

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3 years ago
When sodium chloride, NaCl , dissolves in water, the solution contains ___________________ in addition to the water solvent. The
g100num [7]

Answer:

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chloride ion

sodium ion

Explanation:

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Hence, when sodium chloride is dissolved in water, sodium ions and chloride ions are released in solution.

Water has a dipole moment. Hence, the chloride ions are attracted to hydrogen (the positive end of the dipole) while sodium ions are attracted to oxygen (the negative end of the dipole).

This is how the solid is dissolved in water.

4 0
3 years ago
How many Hydrogen atoms are there in 5 g of NH3? (molar mass of NH3 = 17<br>g/mol)​
goldfiish [28.3K]

Answer:5.309 × 10²⁴ atoms.

Explanation:

Given that

molar mass of NH3 = 17 g/mol

Mass of NH3 = 5g

Therefore, No of moles of NH3 = Mass/ molar mass

=  5g/ 17g/mol

= 0.294 moles.

I  mole = 6.02 × 10²³ atoms

Therefore  the number of hydrogen atoms in a 0.294 moles of ammonia  gives us

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5 0
3 years ago
A 5.00 gram sample of an oxide of lead PbxOy contains 4.33 g of lead. Determine simplest formula for the compund
Harrizon [31]

Answer: The empirical formula is PbO_2

Explanation:

Mass of Pb =  4.33 g

Mass of O = (5.00-4.33) g = 0.67 g

Step 1 : convert given masses into moles

Moles of Pb =\frac{\text{ given mass of Pb}}{\text{ molar mass of Pb}}= \frac{4.33g}{207g/mole}=0.021moles

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Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Pb = \frac{0.021}{0.021}=1

For O = \frac{0.042}{0.021}=2

The ratio of Pb O=  1: 2

Hence the empirical formula is PbO_2

6 0
3 years ago
What kind of chemical bonds are represented by the product in the following diagram?
katovenus [111]
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4 0
3 years ago
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