Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
burninh fossil fuels is not an example
Answer:
50 g Sucrose
Explanation:
Step 1: Given data
- Concentration of the solution: 2.5%
Step 2: Calculate the mass of sucrose needed to prepare the solution
The concentration of the solution is 2.5%, that is, there are 2.5 g of sucrose (solute) every 100 g of solution. The mass of sucrose needed to prepare 2000 g of solution is:
2000 g Solution × 2.5 g Sucrose/100 g Solution = 50 g Sucrose
Significant figures communicates the level of precision in measurements.
Answer:
An example for gaining potential energy would be: A glass bottle on the top of a high shelf would have more high potential energy than a glass bottle on the middle or bottom shelf because it has a long way or more farther to fall down or brake.
Explanation:
Remember Potential Energy is the restored energy of an object has.
I hope this helps you!
