Explanation:
The given data is as follows.
T =
= (120 + 273.15)K = 393.15 K,
As it is given that it is an equimolar mixture of n-pentane and isopentane.
So,
= 0.5 and
= 0.5
According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.
(393.15 K) = 9.2 bar
(393.15 K) = 10.5 bar
Hence, we will calculate the partial pressure of each component as follows.
![p_{1} = x_{1} \times p^{sat}_{1}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20x_%7B1%7D%20%5Ctimes%20p%5E%7Bsat%7D_%7B1%7D)
= ![0.5 \times 9.2 bar](https://tex.z-dn.net/?f=0.5%20%5Ctimes%209.2%20bar)
= 4.6 bar
and, ![p_{2} = x_{2} \times p^{sat}_{2}](https://tex.z-dn.net/?f=p_%7B2%7D%20%3D%20x_%7B2%7D%20%5Ctimes%20p%5E%7Bsat%7D_%7B2%7D)
= ![0.5 \times 10.5 bar](https://tex.z-dn.net/?f=0.5%20%5Ctimes%2010.5%20bar)
= 5.25 bar
Therefore, the bubble pressure will be as follows.
P =
= 4.6 bar + 5.25 bar
= 9.85 bar
Now, we will calculate the vapor composition as follows.
![y_{1} = \frac{p_{1}}{p}](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D%20%5Cfrac%7Bp_%7B1%7D%7D%7Bp%7D)
= ![\frac{4.6}{9.85}](https://tex.z-dn.net/?f=%5Cfrac%7B4.6%7D%7B9.85%7D)
= 0.467
and, ![y_{2} = \frac{p_{2}}{p}](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D%20%5Cfrac%7Bp_%7B2%7D%7D%7Bp%7D)
= ![\frac{5.25}{9.85}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7B9.85%7D)
= 0.527
Calculate the dew point as follows.
= 0.5,
= 0.5
![\frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BP%7D%20%3D%20%5Csum%20%5Cfrac%7By_%7B1%7D%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
![\frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BP%7D%20%3D%20%5Cfrac%7B0.5%7D%7B9.2%7D%20%2B%20%5Cfrac%7B0.5%7D%7B10.2%7D)
= 0.101966
P = 9.807
Composition of the liquid phase is
and its formula is as follows.
![x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}](https://tex.z-dn.net/?f=x_%7Bi%7D%20%3D%20%5Cfrac%7By_%7Bi%7D%20%5Ctimes%20P%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
= ![\frac{0.5 \times 9.807}{9.2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5%20%5Ctimes%209.807%7D%7B9.2%7D)
= 0.5329
![x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}](https://tex.z-dn.net/?f=x_%7Bz%7D%20%3D%20%5Cfrac%7By_%7Bi%7D%20%5Ctimes%20P%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
= ![\frac{0.5 \times 9.807}{10.5}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5%20%5Ctimes%209.807%7D%7B10.5%7D)
= 0.467
Answer:
Atoms or molecules
Explanation:
Because if molecules are heated or colded the can be liquid or solid
Answer:
Tell students that sometimes when two (or more) substances are mixed together, a change occurs and another substance (or substances) is created. This is called a chemical reaction. Gas may form, heat may be produced, and color may change. These types of changes indicate that a chemical reaction has occurred.
The delta G for the dissociation is 87,865 joule/kg.
The process is non-spontaneous because the value of Gibbs free energy is positive.
<h3>What is dissociation?</h3>
The breaking up of a compound into a simpler form that can be recombined under other conditions.
Given,
![\bold{2NH_3 (g) = N_2(g) + 3H_2(g)}](https://tex.z-dn.net/?f=%5Cbold%7B2NH_3%20%28g%29%20%3D%20N_2%28g%29%20%2B%203H_2%28g%29%7D)
H = 145 kJ
Delta S = 195 J/k
Determining the G using the following process:
G = H -TS
![\bold{G = (145\times10^3 J) -(293K \times 195 J/K})](https://tex.z-dn.net/?f=%5Cbold%7BG%20%3D%20%28145%5Ctimes10%5E3%20J%29%20-%28293K%20%5Ctimes%20195%20J%2FK%7D%29)
G = 87,865 Joules/K
Thus, the value of Delta G is 87,865 and the process is non-spontaneous.
Learn more about dissociation here:
brainly.com/question/4431132