Answer:
24.32 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (Mg–24):
Mass of A = 24 amu
Abundance (A%) = 79%
Isotope B (Mg–25):
Mass of B = 25 amu
Abundance (B%) = 10%
Isotope C (Mg–26):
Mass of C = 26 amu
Abundance (C%) = 11%
Average atomic mass of Mg =?
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(24 × 79)/100] + [(25 × 10)/100] + [(26 × 11)/100]
= 18.96 + 2.5 + 2.86
= 24.32 amu
Thus, the average atomic mass of Mg is 24.32 amu
<u>Answer:</u> The atomic radius of iron is 128 pm.
<u>Explanation:</u>
To calculate the radius of the metal having FCC crystal lattice, the relationship between edge length and radius follows:
Where,
a = edge length = 362 pm
r = atomic radius of iron = ?
Plugging values in above equation, we get:
Hence, the atomic radius of iron is 128 pm.
You get 42 when you multiply 6 & 7.
We are asked to solve for the arc length of the intercepted arc and the formula is shown below:
Arc length = 2*pi*r(central angle/360°)
r = 5 feet
central angle = 10°
Solving for the arc length, we have:
Arc length = 2*3.14*5 (10/360)
Arc length = 0.872 feet
The arc length is 0.872 feet.
Answer:
1.will not
2.crushing a rock
3.changes in the phase of mater
Explanation:
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