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Naddika [18.5K]
2 years ago
6

When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change. Classify each ca

se as stable, unstable, or neutral
Physics
2 answers:
slavikrds [6]2 years ago
8 0

The three types of equilibrium in an object are;  stable, unstable, or neutral equilibrium.

<h3>What is equilibrium?</h3>

The term equilibrium refers to a situation in which all the forces acting on an object are balanced such that the object does not move. The question is incomplete as the images are missing.

There are three types of equilibrium:

  • Stable equilibrium: In a stable equilibrium, the object returns to rest in its original place when displlaced.
  • Unstable equilibrium: In this type of equilibrium, the body moves further away from its original position when displaced.
  • Neutral equilibrium: In this type of equilibrium, the object comes to rest in a new position when displaced.

Learn more equilibrium of forces: brainly.com/question/12262457

Stolb23 [73]2 years ago
7 0

When an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.

<h3>What is the equilibrium state of a standing object?</h3>

Equilibrium is the location of the body, in which the body be static or in motion and does not change it with respect to time.

The equilibrium of an object can be classified in the 3 following types.

  • Stable Equilibrium- Stable equilibrium is the condition, in which the object gains its position back after displacing it.
  • Unstable Equilibrium-Unstable equilibrium is the condition, in which the object does not gain its position back after displacing it.
  • Neutral Equilibrium-Natural equilibrium is the condition, in which the object displace from its position and there is no force acting on it.

When an object standing on the floor is tipped, the height of its center of gravity (cg) may or may not change.

The stability of object demands in the center of gravity. Lower the value of CG, results in more stable object. For each case,

  • Stable-Center of gravity is increased when tipped.
  • Unstable-Center of gravity is decreased when tipped.
  • Natural-Center of gravity is remained at same level when tipped.

Thus, when an object standing on the floor is tipped, the height of its center of gravity (cg) for each case as stable, unstable, or neutral may increase, decreased and remain same respectively.

Learn more about the equilibrium state here;

brainly.com/question/1233365

#SPJ4

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Answer:

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Explanation:

Given that,

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The general solution for the above differential equation is

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(a)

since time is 0 then mass is one meter below

so x(0) = 1

Also it start from rest , that implies , velocity is 0 and time is 0

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substitute the initial condition

C_1 +C_2 = 1

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Solve the above equation to get C₁ and C₂

C_1 =\frac{7}{4} and C_2 = -\frac{3}{4}

substitute for C₁ and C₂ in general solution

x(t) = \frac{7}{4} e^{-3t}-\frac{3}{4} e^{-7t}

Thus the required value is x(t) = \frac{7}{4} e^{-3t}-\frac{3}{4} e^{-7t}

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