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Semenov [28]
2 years ago
7

Which are true for a photon. (Choose 3)

Physics
1 answer:
SVEN [57.7K]2 years ago
6 0
The last one






Xjjxueuwuduchjdnrnn Brendan hush she j
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Manufactured bolts can’t be too long or too short or they might not fit where they need to. Help determine which bolts will work
Sever21 [200]
What is the longest the bolt can be and still be acceptable
5 0
3 years ago
A 0.54 kg air hockey puck is initially at rest. What will it's kinetic energy energy be after a net force of 0.56 N acts on it f
Rufina [12.5K]

Answer:

Kf = 470 mJ

Explanation:

  • According the work-energy theorem, the change in the kinetic energy of one object, is equal to the net work done on it.
  • Since the puck is initially at rest, the change is kinetic energy is just the final kinetic energy of the puck.
  • Assuming that the net force is horizontal, and causes a horizontal displacement also, we can find the net work on the puck as follows:

       W_{net} = F_{net} * \Delta X = 0.56 N * 0.84 m = 0.47 J = 470 mJ (1)

  • As we have already said, (1) is equal to the final kinetic energy of the puck:
  • ⇒ Kf = 470 mJ  (2)
8 0
3 years ago
A simple pendulum has a period of 2.5 s. What is its period if its length is increased by a factor of four?
Svetach [21]

Answer:

Its period if its length is increased by a factor of four is 5 s.

Explanation:

The period of a simple pendulum is given by;

T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{l}{g} } \\\\ \frac{T^2}{4\pi^2} = \frac{l}{g}\\\\\frac{T^2}{l} = \frac{4\pi^2}{g} \\\\let \ \frac{4\pi^2}{g}  \ be \ constant \\\\\frac{T_1^2}{l_1}  = \frac{T_2^2}{l_2} \\\\

Given;

initial period, T₁ = 2.5

initial length, = L₁

new length, L₂ = 4L₁

the new period, T₂ = ?

\frac{T_1^2}{l_1}  = \frac{T_2^2}{l_2} \\\\T_2^2 = \frac{T_1^2 l_2}{l_1} \\\\T_2 = \sqrt{\frac{T_1^2 l_2}{l_1}} \\\\  T_2 = \sqrt{\frac{(2.5)^2 \ \times \ 4l_1}{l_1}}\\\\  T_2 =\sqrt{(2.5)^2 \ \times \ 4}\\\\T_2 = \sqrt{25} \\\\T_2 = 5\ s

Therefore, its period if its length is increased by a factor of four is 5 s.

5 0
2 years ago
Which two options are forms of kinetic energy?
Georgia [21]

Answer:

A, C

Explanation:

SOUND ENERGY - energy from sound

MAGNETIC ENERGY - energy with magnetism

7 0
2 years ago
Read 2 more answers
Two children (m = 40 kg each) stand opposite each other on the edge of a merry-go-round. The merry-go-round, which has a mass M
s344n2d4d5 [400]

Answer:

Explanation:

Initially the two boys were sitting on the periphery , total moment of inertia

= 1/2 M  r² + 2mr²     ; M is mass of the merry go round , m is mass of each boy and r is the radius

1/2 x 200 x 2² + 2 x 40 x 2²

= 400 + 320

I₁ =  720 kg m²

Finally  the two boys were sitting at the middle  , total moment of inertia

= 1/2 M  r² + 2m( r/2)²     ; M is mass of the merry go round , m is mass of each boy and r is the radius

1/2 x 200 x 2² + 2 x 40 x 1²

= 400 + 80

I₂  = 480

Now the system will obey law of coservation of angular momentum because no torque is acting on the system.

I₁ω₁ =  I₂ω₂ ,         I₁  and ω₁  are moment of inertia and angular velocity of first case and  I₂  and ω₂ are of second case.

720 X 12 = 480 ω₂

ω₂ = 18 rad / s

3 0
3 years ago
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