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3 years ago

How much would you weigh on an imaginary planet that has no gravitational force?

Physics

1 answer:

GarryVolchara [31]3 years ago

5 0

0kg

If the gravitational pull is zero and I multiply by mass I get a zero

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Transverse waves are sent along a 5.00-m-long string with a speed of 30.00 m/s. The string is under a tension of 10.00 N. What i

Kipish [7]

Answer:

0.055 kg

Explanation:

Given that

Length of the string, l = 5 m

Speed of the wave, v = 30 m/s

Tension on the string, F(t) = 10N

From the formula written in the attachment, we have

v = velocity of the wave, in m/s

F(t) = Tension on the string, in N

U = Mass per length of the string, in kg/m

m = Mass of the string, in kg

l = Length of the string, in m

See attachment for the calculation

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3 years ago

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Anarel [89]

Answer:

The light bulb would glow brighter.

Explanation:

Resistance is the opposition to current flow and in Ohm's law is represented as a constant in the equation V = IR with V the voltage, I the current and R the resistance.

Now let's assume we are in a series circuit that has only one path for electricity to follow to better explain what would happen to a light bulb if the voltage increased but the resistance stayed the same. Based on ohm's law equation, the voltage is directly proportional to the current and the resistance is constant. An increase in the voltage is therefore an increase in the current which flows throught the light bulb making it glow brighter while a decrease in voltage results in a decrease in current flowing through the light bulb making it dim.

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3 years ago

What happens to the heat energy the particles receive during convection and conduction?

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The particals speed up

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PLEASE HELP IF YOUR GOOD AT PHYSICS!!!The speed of a bullet train is measured to be 312.0 mph 3.9 mph. What is the percent

IgorC [24]

Answer: D

Explanation:

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2 years ago

How to change V=72km/hr to m/s

lapo4ka [179]

Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).

Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr. They'll only
change the units.

(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)

= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)

= 20 meter/second

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3 years ago

How much would you weigh on an imaginary planet that has no gravitational force?​

How much would you weigh on an imaginary planet that has no gravitational force?