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serious [3.7K]
3 years ago
7

How much would you weigh on an imaginary planet that has no gravitational force?​

Physics
1 answer:
GarryVolchara [31]3 years ago
5 0

0kg

If the gravitational pull is zero and I multiply by mass I get a zero

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What is time and speed and acceleration
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Acceleration is the rate of change of velocity with time.Acceleration occurs anytime an object's speed increases or decreases, or it changes direction. Much like velocity, there are two kinds of acceleration: average and instantaneous. Average acceleration is determined over a "long" time interval.

Explanation:

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What r photons? <br> ........................,........,..........
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On topographic maps, contour lines that are farther apart indicate what ?
gladu [14]

Answer:

if I am correct, they indicate less steep terrain. think of it as the steeper the terrain the closer together the lines would be. hope that makes sense for you guys.

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2 years ago
What is evaporation? Condensation? Drag the terms on the left to the appropriate blanks on the right to complete the sentences.
krok68 [10]

Answer:

Evaporation is the physical change in which a substance converts from its <u>liquid</u> state to its <u>gaseous</u> state. Condensation is the physical change in which a substance converts from its <u>gaseous</u> state to its <u>liquid</u> state.

Explanation:

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7 0
3 years ago
Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 168 cm , but its circumference is decreasi
DedPeter [7]

Answer:

103.1 V

Explanation:

We are given that

Initial circumference=C=168 cm

\frac{dC}{dt}=-15cm/s

Magnetic field,B=0.9 T

We have to find the magnitude of the  emf induced in the loop after exactly time 8 s has passed since the circumference of the loop started to decrease.

Magnetic flux=\phi=BA=B(\pi r^2)

Circumference,C=2\pi r

r=\frac{C}{2\pi}

r=\frac{168}{2\pi} cm

\frac{dr}{dt}=\frac{1}{2\pi}\frac{dC}{dt}=\frac{1}{2\pi}(-15)=-\frac{15}{2\pi} cm/s

\int dr=-\int \frac{15}{2\pi}dt

r=-\frac{15}{2\pi}t+C

When t=0

r=\frac{168}{2\pi}

\frac{168}{2\pi}=C

r=-\frac{15}{2\pi}t+\frac{168}{2\pi}

E=-\frac{d\phi}{dt}=-\frac{d(B\pi r^2)}{dt}=-2\pi rB\frac{dr}{dt}

E=-2\pi(-\frac{5}{2\pi}t+\frac{168}{2\pi})B\times -\frac{15}{2\pi}

t=8 s

B=0.9

E=2\pi\times \frac{15}{2\pi}\times 0.9(-\frac{15}{2\pi}(8)+\frac{168}{2\pi})

E=103.1 V

6 0
3 years ago
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