Yes potential increases while kinetic decreases
Velocity = displacement/time
I hope i helped you <33
Answer:
From the data we know that runner A and runner B are 11 km apart from the start because (6+5) km
So the runner from the east direction has distance as unknown km, rate= 9 k/h ; time= d/r=x/9 hr
So runner towards the west will be
distance = 11-x, rate= 8 k/h, time = d/r = (11-x)/8
So equating east and west time we have
x/9= (11-x)/8
8x=99-9x
17x=99
x=5.92 km
That is the distance covered by runner towards the east and he will meet the runner toward the west at
6-5.92=0.08 km west of the flagpole.
Answer:
Explanation:
It is a case of oscillation by simple pendulum . Expression for simple pendulum is given as follows
T = 
where T is time period , l is length of pendulum and g is acceleration due to gravity .
, f is frequency of oscillation
For the given case
subsequently length becomes half so
dividing
f = 
frequency of oscillation becomes √2 times.
Hello,
This is true. Net force can be calculated using the equation F = ma, where f is net force, m is mass, and a is acceleration. Simply multiply mass and acceleration to obtain the net force being exerted on the object.
True
Hope this helps!
