the equation of the tangent line must be passed on a point A (a,b) and
perpendicular to the radius of the circle. <span>
I will take an example for a clear explanation:
let x² + y² = 4 is the equation of the circle,
its center is C(0,0). And we assume that the tangent line passes to the point
A(2.3).
</span>since the tangent passes to the A(2,3), the line must be perpendicular to the radius of the circle.
<span>Let's find the equation of the line parallel to the radius.</span>
<span>The line passes to the A(2,3) and C (0,0). y= ax+b is the standard form of the equation. AC(-2, -3) is a vector parallel to CM(x, y).</span>
det(AC, CM)= -2y +3x =0, is the equation of the line // to the radius.
let's find the equation of the line perpendicular to this previous line.
let M a point which lies on the line. so MA.AC=0 (scalar product),
it is (2-x, 3-y) . (-2, -3)= -4+4x + -9+3y=4x +3y -13=0 is the equation of tangent
Answer: 115.38N
Explanation:
Firstly, let's determine the constant.
Hooke's law was discovered by Robert Hooke in 1660.
Using hooke's law which states that provided the elastic limit of an elastic material is not exceeded, the force is equal to the extension applied provided all factors are kept constant.
Hooke's Law is a principle of physics that states that the force which is needed to extend or compress a spring by some distance is proportional to that distance
Therefore,
Force=kx
K= F/x
Where Force= 75m
x= 0.065m
K= 75/0.065m
K= 1153. 846N
We can use the constant to find the force when the distance that is stretched(x) is known.
Here
Force=kx
F= 1153.846 × 0.10
F= 115.38N
The force required to stretch it by this amount is 115.38N.
Acceleration: is the change in velocity divided by the time it takes for the change to occur. . Acceleration is the change in verity divided by the time it takes to make the change, Acceleration has direction.
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Answer:
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