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3 years ago

An 80 kg object has a µk = 0.35 and a µs = 0.60. Assuming it is on a flat surface

Physics

1 answer:

Over [174]3 years ago

6 0

Answer:

What is the normal force on the object (draw a diagram if needed)

784 N

How much force is required to get the object to start to move from rest (max static friction)?

470.4 N

When the object starts moving, what is the force of kinetic friction?

274.4 N

If the moving object has a tension force of 300N to the right pulling it, what is the net force on the object in the horizontal direction? 784 N

What is the acceleration (with direction) of the object based on your answer for part d? Remember that a = net force/m.

Explanation:

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A paragraph that can serve the specific purpose of creating a special effect within the essay is called?

Katarina [22]

Its b.functional paragraph because writers use this for interest presents and special effects

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3 years ago

Read 2 more answers

As part of a safety investigation, two 1900 kg cars traveling at 20 m/s are crashed into different barriers. Part A Find the ave

DedPeter [7]

Answer:

- $29.2\times 10^{3} N$

Explanation:

We are given that

Mass of cars= m=1900 kg

Initial speed of car=u=20 m/s

Final speed of car=v=0

Time= $\Delta t$ =1.3 s

We have to find the average force exerted on the car.

Average force= $\frac{change\;in\;momentum}{\Delta t}$

$F_{avg}=\frac{mv-mu}{1.3}$

$F_{avg}=\frac{1900(0)-1900(20)}{1.3}$

$F_{avg}=\frac{-38000}{1.3}=-29.2\times 10^{3} N$

Hence, the average force exerted on the car that hits a line of water barrels=- $29.2\times 10^{3} N$

8 0

3 years ago

Help me please this is for physics

Yuri [45]

<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

$23.1m/s$

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

$T=\frac{2_{v0~sin 0} }{g}$

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

$\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}$

⇒ 2 × $_{v0}$ ×0.8910= 9.8 × 4.2

⇒ $\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}$

$\boxed{{v0} =23.1m/s}$

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0

2 years ago

An object accelerating only under the force of gravity is A) free fall or B) acceleration due to gravity

Andrews [41]

-- An object acted on by only the force of gravity, on or near Earth's surface,
accelerates downward at the rate of about 9.8 m/s² without air resistance.

-- That number is "the acceleration due to gravity, on Earth".

-- The object in that situation is said to be in "free fall".

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3 years ago

A ball is moving at 3 m/s and has a momentum of 48 kg m/s. What is the ball's mass?

jonny [76]

$P = mv \\ m = \frac{P}{v} \\$

3 0

3 years ago