What does the angular momentum quantum number determine? Check all that apply.
2 answers:
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Initial velocity of the object: 5 m/s
Explanation:
The figure in the problem is missing: find it in attachment.
The graph in the figure represents the velocity of an object (v) versus the time passed (t).
Here we are asked to find the initial velocity of the object.
This means that we have to find the velocity of the object when the time is zero, so when
t = 0
By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then
v = 5 m/s
Therefore, the initial velocity of the object is 5 m/s.
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Answer:
The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South
Explanation:
The given collision parameters are;
The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision
The mass of the first disk, m₁ = 50.0 g
The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i
The mass of the second disk, m₂ = 60.0 g
The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j
The mass of the third disk, m₃ = 100.0 g
The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i
The mass of the fourth disk, m₄ = 40.0 g
The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j
Therefore, the total initial momentum of the four velcro-lined air-hockey disk, is given as follows;
= m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)
∴ = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j
∴ = -20·i + 130·j
By the law of conservation of linear momentum, we have;
= -20·i + 130·j
Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0
∴ m = 250.0 g
Let, "v" represent the final velocity of the four disks moving as one after the collision
We have;
= m × v = 250.0 × v = -20·i + 130·j
∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j
The final velocity of the four disks after collision, v = -0.08·i + 0.52·j
The magnitude of the final velocity, = √((-0.08)² + (0.52)²) ≈ 0.526
≈ 0.526 m/s
The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°
The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South
Answer
given,
near point = 18 cm
far point = 40 cm
a) The lens should form an upright, virtual image at far point from the distant object.
therefore, f = q = -40 cm = -0.4 m
where f is the focal length.
the required power
P = -2.5 D
b) If the lens is used the Person's near point
The lens should form an upright, virtual image at near point from the distant object should be q = - 18 cm = -0.18 m
p = 32.72 cm
The person's near point is 32.72 cm