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2 years ago

Can chlorine become sulfur

Chemistry

2 answers:

babunello [35]2 years ago

8 0

Yes sir it can. Or ma’am

aev [14]2 years ago

8 0

Yes, this is how. SCl2 is produced by the chlorination of either elemental sulfur or disulfur dichloride. The process occurs in a series of steps, some of which are: S8 + 4 Cl2 → 4 S2Cl2; ΔH = −58.2 kJ/mol. S2Cl2 + Cl2 ↔ 2 SCl2; ΔH = −40.6 kJ/mol.

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A hot air balloon is filled with 15 moles helium gas and 5 moles nitrogen gas. What is the volume of the balloon at 1.01 atm and

kvasek [131]

Given:

Moles of He = 15

Moles of N2 = 5

Pressure (P) = 1.01 atm

Temperature (T) = 300 K

To determine:

The volume (V) of the balloon

Explanation:

From the ideal gas law:

PV = nRT

where P = pressure of the gas

V = volume

n = number of moles of the gas

T = temperature

R = gas constant = 0.0821 L-atm/mol-K

In this case we have:-

n(total) = 15 + 5 = 20 moles

P = 1.01 atm and T = 300K

V = nRT/P = 20 moles * 0.0821 L-atm/mol-K * 300 K/1.01 atm = 487.7 L

Ans: Volume of the balloon is around 488 L

3 0

3 years ago

If the absorbance of a KMnO4 solution of unknown concentration is 0.633, calculate the concentration of KMnO4 in the solution.

solong [7]

The molar Concentration of KMnO₄ is 0.000219 M

Concentration is the abundance of a constituent divided by means of the overall extent of an aggregate. numerous styles of mathematical description may be outstanding: mass awareness, molar awareness, variety concentration, and quantity awareness.

y is absorbance

x is the molar concentration of KMnO_4

y = 4.84E + 03x - 2.26E - 01

0.833 = 4.84 * 10⁺⁰³ x - 2.26 * 10⁻¹

1.059 = 4.84 * 10⁺⁰³ x

X = 0.000219 M

Hence, The molar Concentration of KMnO₄ is 0.000219 M

Learn more about concentration here:-brainly.com/question/14469428

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3 0

1 year ago

1.25 cm is the same distance as ? 12.5 Km 12.5 mm 12.5 dm 12.5 m

pogonyaev

Answer:

12.5mm

Explanation:

1cm = 10mm

so you need to multiply the 1.25 by 10 to get it in mm.

6 0

3 years ago

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OlgaM077 [116]

Answer:

2AL(ClO3)3 → 2ALCl3 + 9O2

Explanation:

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2 years ago

Of the following transitions in the Bohr hydrogen atom, the ________ transition results in the emission of the lowest-energy pho

Sladkaya [172]

N=6 ——> n=1
hope this helps!

5 0

3 years ago