Answer;
D, Xe (g)
Solution and explanation;
If 2g has a volume of 340ml.
Density is 1000/340*2 = 5.88g/litre.
-This rules out the two solids, choices 2) &3)
If 1 litre has mass 5.88g,
then 22.4 liters (volume at STP) has mass 5.88*22.4 = 131.8g/mol
molar mass Br2 = 80*2 = 160g/mol NO
molar mass Xe = 131.3g/mol = YES.
Answer is Xe
1st qn - B
2nd qn - A
Last qn - Yes
The required mass of argon in given number of atoms of argon is 155.61 grams.
<h3>What is Avogadro's number?</h3>
Avogadro's number is the number of atoms which are present in 1 mole of any substance and it is equal to 6.022×10²³.
Relation between the mass and moles of any substance will be represented as:
- n = W/M, where
- W = given mass
- M = molar mass
So, moles of argon will be calculated by using given number of atoms as:
Moles = 2.4×10²⁴ atoms / 6.022×10²³ atoms per mole
Moles = 3.9 moles
Now mass will be:
W = (3.9mol)(39.9g/mol) = 155.61 g
Hence required mass of argon is 155.6g.
To know more about Avogadro's number, visit the below link:
brainly.com/question/1513182
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I’m pretty sure it’s A mid-ocean ridges
