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Lubov Fominskaja [6]
3 years ago
15

Which is one way to check 102 divided 6 =17?

Mathematics
2 answers:
eimsori [14]3 years ago
8 0
102 ÷ 6 = 17

17 × 6 = 102
Colt1911 [192]3 years ago
7 0
Just multiply 17 and 6 and it should equal 102! and if not then its wrong.
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Is (1, 2) a solution to the inequality 6x - y> 3?
Lostsunrise [7]

Answer:

<u><em>Yes.</em></u>

Step-by-step explanation:

<em>To find the answer we will put it into the equation, since</em><em><u> x = 1 and y = 2</u></em><em> we will write it like this, </em><u><em>6(1) - 2 > 3.</em></u><em>  Since </em><u><em>6 x 1 = 6</em></u><em>, we will now </em><u><em>subtract 6 from 2 which equals 4</em></u><em>.  Therefore, the equation is </em><u><em>correct because 4 is bigger than 3.</em></u>

5 0
3 years ago
Complete sequence. 4.15, 6.30, 8.45. How do I get answer?
azamat
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6 0
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Doubling both the area of the bases and the height of a prism doubles its volume. T/F
xenn [34]

Answer:

True.

Step-by-step explanation:

7 0
3 years ago
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What are the measurements of the little 2 small cube things on each side, better yet what's the surface area? Thank you
Arisa [49]

<u>Answer:</u>

  • 166 units²

<u>Step-by-step explanation:</u>

<u>We know that:</u>

  • W = 7
  • L = 5
  • H = 4

<u>Surface area is the area of the faces of the cuboid.</u>

<u>Work:</u>

  • => 2(7 x 4) + 2(5 x 4) + 2(5 x 7)
  • => 2(28) + 2(20) + 2(35)
  • => 56 + 40 + 70
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Hence, <u>Option C is correct.</u>

Hoped this helped.

BrainiacUser1357

4 0
2 years ago
Apply the properties of exponents to rewrite each expression in the form kxn, where nn is an integer and x ≠0
professor190 [17]

Answer:

The expression will be 0.333x^{-2}

Step-by-step explanation:

We have given expression \frac{x^{-3}x^5}{3x^4}

We know the property of exponent that when two function are divided then the power of exponent is subtracted and when there is multiplication of two function then exponent is added

So \frac{x^{-3}x^5}{3x^4}=\frac{x^{2}}{3x^4}=0.333x^{-2}

So the expression will be 0.333x^{-2}

4 0
3 years ago
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