Question

A skier accelerates to a speed of 56 m/s over a distance of 151 m. Determine the acceleration (assume uniform) of the skier.

Answer 1

The acceleration of the skier over the distance traveled is 10.38 m/s²

The given parameters;

• Initial velocity of the skier, u = 56 m/s
• Distance covered by the skier, s = 151 m

Acceleration is defined as the change in velocity per change in time of motion.

The magnitude of the acceleration of the skier is calculated as follows;

$v^2 =u^2 - 2as$

where;

v is the final velocity at the end of 151 m = 0

$0 = 56^2 -(2\times 151)a\\\\302a = 3136\\\\a = \frac{3136}{302} \\\\a = 10.38 \ m/s^2$

Thus, the acceleration of the skier over the distance traveled is 10.38 m/s²

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