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Luda [366]
3 years ago
13

The gravitational force between the sun and every object in the solar system helps keep each object in its own unique orbit arou

nd the sun. Lesson 3. 03 Question 2 options: True False.
Physics
2 answers:
saw5 [17]3 years ago
8 0

Answer:

True

Explanation:

i did the Quiz

Kazeer [188]3 years ago
3 0

Answer:

A: true

Explanation:

I took the test its right, trust me I got 100%

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The secondary coil of a neon sign transformer provides 7500 V at 0.01 A. The primary coil operates on 120 V. What is the input c
nikitadnepr [17]

Answer:

0.625 A

Explanation:

Vs = 7500 V, Is = 0.01 A

Vp = 120 V

Let the primary current be Ip.

As the transformer is ideal, so input power is equal to the output power

Vp x Ip = Vs x Is

120 x Ip = 7500 x 0.01

Ip = 0.625 A

8 0
3 years ago
Where is most of the mass of an atom located? in the nucleus in the orbits in the electrons it is split between the nucleus and
yulyashka [42]
Most of the mass is located in the nucleus as suggested by Rutherford's gold foil experiment.
7 0
3 years ago
Read 2 more answers
A vehicle travels from a 30m marker to a 100m marker. What is the change in distance?
sesenic [268]
The change in distance is 30 because if you subtract both number you'll get 30
3 0
4 years ago
Read 2 more answers
Two particles, each of charge Q, are fixed at opposite corners of a square that lies in the plane of the page. A positive test c
amid [387]

Answer:

The magnitude of the net force is √2F.

Explanation:

Since the two particles have the same charge Q, they exert the same force on the test charge; both attractive or repulsive. So, the angle between the two forces is 90° in any case. Now, as we know the magnitude of these forces and that they form a 90° angle, we can use the Pythagorean Theorem to calculate the magnitude of the resultant net force:

F_N=\sqrt{F^{2}+F^{2}}\\\\F_N=\sqrt{2F^{2}}\\\\F_N=\sqrt{2}F

Then, it means that the net force acting on the test charge has a magnitude of √2F.

7 0
3 years ago
A simple pendulum is made by tying a 2.44 kg stone to a string 4.57 m long. The stone is projected perpendicularly to the string
alexdok [17]

Answer:

v_{max}=8.2226m/s

Explanation:

The problem is solved using the law of conservation of energy,

So

mgL(1-cos\theta)+\frac{1}{2}mv^2_0=\frac{1}{2}mv^2_{max}

v_{max}=\sqrt{2gL(1-cos\theta)+v^2_0}

v_{max}=\sqrt{2(9.8)(4.57)(1-cos(69.4))+8^2}

v_{max}=8.2226m/s

8 0
3 years ago
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