Answer:
Action-Reaction Force Examples in Everyday Life
Recoil of a Gun.
Swimming.
Pushing the Wall.
Diving off a Raft.
Space Shuttle.
Explanation:
hope this helps
Since you are referring to the TI-203 and TI-205, you need to know the actual masses of these two isotopes. TI-203 has 202.9723 amu and TI-205 has 204.9744 amu. Since you are concluding that this Thallium have 29.5% (Ti-203) and 70.5% (Ti-205), you need to multiply the percentage to the actual masses of the isotopes. With that, you should be able to get 204.3833 amu
To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and sum of forces in bodies.
From Newton's second law we understand that
Gravity at this case)
Where,
m = mass
a= acceleration
Also we know that
Part A) The buoyant force acting on the balloon is given as
As mass is equal to the density and Volume and acceleration equal to Gravity constant
PART B) The forces acting on the balloon would be given by the upper thrust force given by the fluid and its weight, then
PART C) The additional mass that can the balloon support in equilibrium is given as
The "pitch" of a sound is the impression your brain forms
that corresponds to the frequency of the sound wave.
When the frequency is high, your brain says "high pitch".
When the frequency is low, your brain says "low pitch".
Answer:
3.46 A
Explanation:
The force (F) exerted on a wire of a particular length (L) carrying current (I) through a magnetic field (B) at an angle (θ) to the magnetic field is given as
F = (B)(I)(L) sin θ
F = 3.13 N
B = 0.360 T
I = ?
L = 2.50 m
θ = 79°
3.13 = (0.360 × I × 2.5 × sin 79°)
0.8835 I = 3.13
I = 3.54 A
But this is the resultant current in this magnetic field.
Since the two wires are conducting current in opposite directions,
Resultant current = 7 - (current in the other wire)
Current in the other wire = 7 - 3.54 = 3.46 A
