To attain equilibrium there should be net force on the body, so that the object will not be in motion. so for a body of wb, any weight will do as long as there is no external force that is applied to it. the only force that is acting on it is the weight which is going down, and the normal force which is going up, to counter act the weight. and the net force is zero.
Answer:
Hi there!
The answer to this question is the first choice: Xe 138 (top), 54 (bottom)
Because on the left side it adds up to 240 (top) and 94 (bottom)
and the right side adds up to 102 (top) and 40 (bottom)
to equal both sides, you need 138 more to get 240 on the top and 54 on the bottom to get 94. then you use the bottom number 54, to see what element it is and Xenon is the answer.
F = m a
13 = 6.5 a
a = 2 m/s²
Vf = Vi + a t
Vf = 2.5 + 2(2.1)
Vf = 2.5 + 4.2
Vf = 6.7 m/s
Answer is C
The best ways to determine the safest driving speed are to 1) know the speed limit, and 2) maintain a safe following distance.<span> The safe following distance is to be enough distanced form the vehicle in front of you. But how much is enough?
A </span>driver<span> should ideally stay at least two seconds behind any vehicle that is directly in front of his or her vehicle.</span>
Answer:
x = 0.6034 m
Explanation:
Given
L = 5 m
Wplank = 225 N
Wman = 522 N
d = 1.1 m
x = ?
We have to take sum of torques about the right support point. If the board is just about to tip, the normal force from the left support will be going to zero. So the only torques come from the weight of the plank and the weight of the man.
∑τ = 0 ⇒ τ₁ + τ₂ = 0
Torque come from the weight of the plank = τ₁
Torque come from the weight of the man = τ₂
⇒ τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)
⇒ τ₂ = Wman*x = 522 N*x (clockwise)
then
τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0
⇒ x = 0.6034 m