If the frequency of an electromagnetic wave is too high or too low. A) It cannot be seen. B) It is no longer a wave. C) It is no
1 answer:
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Answer:
F = 2.40 × N
Explanation:
given data
charge q1 = 3.95 nC
x= 0.198 m
charge q2 = 4.96 nC
x= -0.297 m
solution
force on a point charge kept in electric field F = E × q ................1
here E is the magnitude of electric field and q is the magnitude of charge
and
first we will get here electric field at origin
So net field at origin is
E = (Kq2÷r2²) - (kq1÷r1²) ...............2
put here value
E = 9[(4.96÷0.297²)-(3.95÷0.198²)]
E = 400.72 N/C ( negative x direction )
so that force will be
F = 6 × × 400.72
F = 2.40 × N
Answer
When an electron makes transition from a state of higher energy to a state of lower energy it does so by emitting energy in form of radiation in the visible spectrum of light.
Since the basic postulates of the atomic theory is that the energy that the electron possess in it's orbit's takes only discrete values and cannot take any random value thus when an electron makes a transition from a state of higher energy to state of lower energy it will emit radiation with energy equal to difference between the energy levels of the 2 orbit's thus we only observe discrete lines.
Mathematically when an electron makes a transition between states the wavelength of light it releases is given by
where is Rydberg constant
is upper energy level
is lower energy level
thus we can see that only discrete wavelength's are released and not continuous wavelength's of light.