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Helga [31]
3 years ago
11

In the chemical reaction, mg + 2hcl mgcl2 + h2 how many moles of hcl are needed to completely react with 3.5 moles of mg?

Chemistry
1 answer:
Luba_88 [7]3 years ago
6 0
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of Mg to HCl is 1:2
number of Mg moles reacted - 3.5 mol
1 mol of Mg reacts with 2 mol of HCl 
therefore 3.5 mol of Mg requires - 2 x 3.5 = 7.0 mol of HCl 
number of HCl moles required to completely react with 3.5 mol of Mg is 7.0 mol of HCl
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An aqueous KNO3 solution is made using 76.6 g of KNO3 diluted to a total solution volume of 1.84 L. (Assume a density of 1.05 g/
defon

Answer:

The answer to your question is Molarity = 0.41

Explanation:

Data

mass of KNO₃ = 76.6 g

volume = 1.84 l

density = 1.05 g/ml

Process

1.- Calculate the molecular mass of KNO₃

molecular mass = 39 + 14 + (16 x 3) = 101 g

2.- Calculate the number of moles

                      101 g of KNO₃  --------------- 1 mol

                       76.6 g of KNO₃ ------------  x

                        x = (76.6 x 1) / 101

                        x = 0.76 moles

3.- Calculate molarity

Molarity = \frac{number of moles}{volume}

Substitution

Molarity = \frac{0.76}{1.84}

Result

Molarity = 0.41

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3 years ago
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The chart with the information to answer this question may be found in other Brainly's link, so I attach it now.

Answer:

  • Z

Explanation:

To facilitate the accompaniment of the reasoning, I copy the data here:

Object     Motion

  X           3 units left, 3 units right

  Y           6 units right, 18 units right

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The <em>distance</em> is the scalar magnitude that indicates the total length of the path traveled.

The <em>displacement</em> is the vector that indicates how far the end point and the initial point are.

In order to calculate the distance, the displacement and the ratio r = distance/displacement, to check which object has a distance that is three times as great as its displacement, i.e. r = 3, we use this new chart:

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  X          3 units left, 3 units right        3 + 3 = 6       3 - 3 = 0            ∞

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  Z          16 units right, 8 units left       16 + 8 = 24    16 - 8 = 8         3

The ratios were calculated dividing the distance by the displacement: distance / displacement.

For the object Z, that was 24 / 8 = 3. Thus, the object that has a distance that is three times as great as its displacement is the object Z.

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