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Helga [31]
3 years ago
11

In the chemical reaction, mg + 2hcl mgcl2 + h2 how many moles of hcl are needed to completely react with 3.5 moles of mg?

Chemistry
1 answer:
Luba_88 [7]3 years ago
6 0
The balanced equation for the above reaction is as follows;
Mg + 2HCl ---> MgCl₂ + H₂
stoichiometry of Mg to HCl is 1:2
number of Mg moles reacted - 3.5 mol
1 mol of Mg reacts with 2 mol of HCl 
therefore 3.5 mol of Mg requires - 2 x 3.5 = 7.0 mol of HCl 
number of HCl moles required to completely react with 3.5 mol of Mg is 7.0 mol of HCl
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How many molecules of BH3 are in 14.32 grams of BH3?
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Answer:

6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

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When did the water level in Lake Mead become a concern?
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6 0
2 years ago
It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2
Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

n_{HCl}=2*n_{Mg(OH)_2}

And in terms of volumes and concentrations we verify:

V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}

So we use the given data to proof it:

4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0
2 years ago
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 3
Alinara [238K]

<u>61.25 grams</u> of CO can be formed from 35 grams of oxygen.

The molecular mass of oxygen is <u>16 gmol⁻¹</u>

The molecular mass of carbon monoxide is<u> 28 gmol⁻¹</u>

Explanation:

The molar mass of carbon monoxide is molar mass of C added to that of O;

12 + 16 = 28

= 28g/mol

The molar mass of oxygen is 16 g/mol while that of oxygen gas (O₂) is 32 g/mol

Since the ration oxygen to carbon monoxide is 1: 2 moles, we begin to find out how many moles of carbon monoxide are formed by 35 g of oxygen;

35/32 * 2

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Then multiply by the molar mass of carbon monoxide;

70/32 * 28

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