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tigry1 [53]
2 years ago
10

A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force

acting on the bicyclist?
Physics
1 answer:
FromTheMoon [43]2 years ago
4 0

The net force acting on the bicyclist is 11.022 Newton.

<u>Given the following data:</u>

  • Mass of bicyclist = 66 kg
  • Initial velocity = 0.50 m/s
  • Initial velocity = 1.50 m/s
  • Distance traveled = 6.0 meters

To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

Force = mass × acceleration

First of all, we would determine the acceleration by using the third equation of motion;

V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}

Acceleration, a = 0.167 m/s^2

Now, we can find the net force acting on the bicyclist:

Force = 66 × 0.167

<em>Force </em><em>= </em><em>11.022 Newton</em>

Therefore, the net force acting on the bicyclist is 11.022 Newton.

Read more here: brainly.com/question/24029674

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Two solid discs are liked with a belt. The
irakobra [83]

Answer:

ω₂ = 13.09 rad/s

Explanation:

given,

small disk rotating speed = 500 rpm

radius of small disk = R

radius of larger disk = 2 R

rotational speed of larger disk = ?

using the law of conservation of angular momentum, we get

I₁ ω₁ = I₂ ω₂

moment of inertia for solid disk

I = \dfrac{1}{2}MR^2

now,

(\dfrac{1}{2}MR_1^2)\omega_1=(\dfrac{1}{2}MR_2^2)\omega_2

(\dfrac{1}{2}MR^2)\omega_1=(\dfrac{1}{2}M(2R)^2)\omega_2

R^2\times \omega_1= 4 R^2\times \omega_2

\omega_2=\dfrac{\omega_1}{4}

\omega_2=\dfrac{500}{4}

   ω₂ = 125 rpm

and

\omega_2=125\times \dfrac{2\pi}{60}

   ω₂ = 13.09 rad/s

the rotational speed of larger disc is equal to ω₂ = 13.09 rad/s

7 0
3 years ago
Which answer is a scientifically accurate description of velocity?
Tcecarenko [31]

The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

Explanation:

A boat traveling from the dock northward to a 200m mark in the bay in less than 5minutes giving the passengers several more hours to fish is a typical and best example of velocity description.

Velocity is the displacement of a body divided by the time taken.

 Velocity = \frac{displacement}{time}

Displacement is the distance covered in a specific direction. Time is duration of the travel.

Velocity is a vector quantity that has both magnitude and direction. This implies that the value of velocity is recorded with a directional attribute.

We can say velocity is the speed of a body in a given direction

Only the last option gives the displacement of the body and the duration it traveled.

Learn more:

Velocity brainly.com/question/10883914

#learnwithBrainly

5 0
3 years ago
BRAINLIESTTT!! HELP ME!!!
likoan [24]

The efficiency of the scissor is 200%.

<u>Explanation:</u>

Efficiency is defined as the ratio of output of any instrument or device or machine to the input supplied to it. So the greater the output the greater will be the efficiency of the device.

As here the work done by us on the system is said to be 10 J so this will be equal to the input work done on the system. And the work done by the system i.e., the scissor is 20 J, so this will be the output work.

So, the efficiency is the ratio of output to input as shown below.

Efficiency = (\frac {20} {10} ) \times 100 = 200

So, the efficiency of the scissor is 200%.

6 0
3 years ago
Select the correct scientific notation form of this numeral. 106.3
Alja [10]
Scientfic notation 1.063 x 10^2
5 0
4 years ago
An ice block measuring 5cm by 5cm by 5cm has a desity of 5g/cm3. What is the mass of the ice block?
Svetradugi [14.3K]


Density = (mass) / (volume)

Volume of your block = (5cm x 5cm x 5cm) = 125 cm³

5 gm/cm³ = (mass) / (125 cm³)

Multiply each side by (125 cm³):  Mass = 625 gm

Note: 
I don't know what kind of frozen substance you're working with,
but maybe you ought to be careful handling it ... I know that's
not water ice you have there.  The density of water ice is not
5 gm/cm³.  In fact, it's a little less than 1 gm/cm³.  That's why
the ice floats in your soda.

4 0
3 years ago
Read 2 more answers
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