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tigry1 [53]
2 years ago
10

A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force

acting on the bicyclist?
Physics
1 answer:
FromTheMoon [43]2 years ago
4 0

The net force acting on the bicyclist is 11.022 Newton.

<u>Given the following data:</u>

  • Mass of bicyclist = 66 kg
  • Initial velocity = 0.50 m/s
  • Initial velocity = 1.50 m/s
  • Distance traveled = 6.0 meters

To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

Force = mass × acceleration

First of all, we would determine the acceleration by using the third equation of motion;

V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}

Acceleration, a = 0.167 m/s^2

Now, we can find the net force acting on the bicyclist:

Force = 66 × 0.167

<em>Force </em><em>= </em><em>11.022 Newton</em>

Therefore, the net force acting on the bicyclist is 11.022 Newton.

Read more here: brainly.com/question/24029674

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