Question

A 66-kg bicyclist (including the bicycle) accelerates uniformly from 0.50 m/s to 1.50 m/s, traveling 6.0m. What is the net force acting on the bicyclist?

Answer 1

The net force acting on the bicyclist is 11.022 Newton.

Given the following data:

• Mass of bicyclist = 66 kg

• Initial velocity = 0.50 m/s

• Initial velocity = 1.50 m/s

• Distance traveled = 6.0 meters

To find the net force acting on the bicyclist, we would apply Newton's Second Law of Motion:

Mathematically, Newton's Second Law of Motion is given by this formula;

$Force = mass$ × $acceleration$

First of all, we would determine the acceleration by using the third equation of motion;

$V^2 = U^2 + 2aS\\\\1.5^2 = 0.5^2 + 2a(6)\\\\2.25 = 0.25 + 12a\\\\12a = 2.25 - 0.25\\\\12a = 2\\\\a = \frac{2}{12}$

Acceleration, a = 0.167 $m/s^2$

Now, we can find the net force acting on the bicyclist:

$Force = 66$ × $0.167$

Force = 11.022 Newton

Therefore, the net force acting on the bicyclist is 11.022 Newton.

Read more here: brainly.com/question/24029674