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Doss [256]
3 years ago
7

Jon's bathtub is rectangular and its base is 18 ft2. How fast is the water level rising if Jon is filling the tub at a rate of 0

.7 ft3/min?
Physics
1 answer:
Dvinal [7]3 years ago
4 0

To solve this problem we will use the concepts related to the volumetric flow rate, which describes the amount of volume per unit of time, through the Area of the section and the speed of the fluid over it. Mathematically this is:

Q = A*V \rightarrow V = \frac{Q}{A}

Where,

Q = Discharge

A= Cross sectional Area

V = Velocity

Our values are given as,

A = 18ft^2

Q = 0.7ft^3/min

Replacing,

V = \frac{0.7}{18}

V = 0.038ft/min

Therefore the water level rises to a velocity of 0.038ft/min

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If the air resistance is <u>too small</u> that we can approximate it to <u>zero</u> in the calculations, then in free fall the objects will accelerate downwards at 9.8\frac{m}{s^{2}} and hit the ground at approximately the same time.  


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