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Anna71 [15]
3 years ago
9

One astronomer has observed an apparent lengthening of the electromagnetic waves given off by a star. Which of these conclusions

is correct about the star?Its parallax is increasing. It is moving towards Earth. Its wavelength is decreasing. It is moving away from Earth.
Physics
2 answers:
steposvetlana [31]3 years ago
5 0
I think the correct answer from the choices listed above is the last option. The conclusion about the star would be that it is moving away from  Earth. L<span>engthening of the waves means that wavelength getting larger </span>this occurs when a body giving off light is moving away. Hope this answers the question.
MA_775_DIABLO [31]3 years ago
4 0

Answer:

It is moving away from Earth.

Explanation:

The electromagnetic waves given off by a star is bring observed by an astronomer. The waves seem to be lengthening. This means the apparent wavelength of the waves is increasing. It can be explained from Doppler's effect. Doppler's effect states that there is change in apparent wavelength of light when there is relative motion between the source and the observer.

The apparent wavelength decreases when the source and observer approach each other while it increases when they are moving apart.

In the given situation, since the apparent wavelength is increasing, it means the star is moving away from the Earth and we are observing a red shift.

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The ________ is located inside the outdoor condenser unit and receives the low-pressure refrigerant vapor through the suction li
dusya [7]

Answer:

Compressor

Explanation:

Compressor - the compressor is a unit that placed at the inner side of the condenser. The main function of the compressor is to increase the pressure by reducing the volume of air. And this reduced volume of air is compressed for the cleaning purpose of the air tube. While condenser is used for heat exchange which converts steam into liquid form.  

It is advisable not to operate the compressor when the outside temperature is below 65 degrees F.

6 0
3 years ago
Observe: Click Reset. Turn on Show velocity vector and Show velocity components. Set vinitial to 50 m/s and set θ to 45.0 degree
Kobotan [32]

Answer:

v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

Explanation:

In this exercise you are asked to observe the change in velocity in a projectile launch.

If we assume that the friction force is small, the velocity in the x-axis must be constant

         vₓ = v₀ₓ

Therefore, the arrow (red) that represents this movement must not change in magnitude.

In the direction of the y axis, the acceleration of gravity is acting, so the magnitude of the velocity in this axis changes

         v_y = v_{oy} - g t

where the upward direction is positive, so the arrow represents this speed (blue) must decrease, reach zero and grow in a negative direction as time progresses

7 0
3 years ago
Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth's center. Satellite A is to o
Juliette [100K]

(a) 0.473

The potential energy of a satellite orbiting around Earth is given by

U=-\frac{GMm}{R+h}

where

G is the gravitational constant

M is the Earth's mass

m is the satellite's mass

R is the Earth's radius

h is the altitude of the satellite above the Earth's surface

So the potential energy of satellite A is

U_A=-\frac{GMm}{R+h_A}

while potential energy of satellite B is

U_B=-\frac{GMm}{R+h_B}

Therefore the ratio of the potential energy of satellite B to that of satellite A is

\frac{U_B}{U_A}=\frac{R+h_A}{R+h_B}

and using

hA = 5920 km

hB = 19600 km

R = 6370 km

we find

\frac{U_B}{U_A}=\frac{6370+5920}{6370+19600}=0.473

(b) 0.473

The kinetic energy of a satellite orbiting around Earth instead is given by

K=\frac{GMm}{2(R+h)}

So the kinetic energy of satellite A is

K_A=\frac{GMm}{2(R+h_A)}

while kinetic energy of satellite B is

K_B=\frac{GMm}{2(R+h_B)}

Therefore the ratio of the kinetic energy of satellite B to that of satellite A is

\frac{K_B}{K_A}=\frac{R+h_A}{R+h_B}

which is identical to before, so it  gives

\frac{K_B}{K_A}=\frac{6370+5920}{6370+19600}=0.473

(c) Satellite B

The total energy of a satellite in orbit is given by

E=U+K = -\frac{GMm}{R+h}+\frac{GMm}{2(R+h)}=-\frac{GMm}{2(R+h)}

We see that the total energy is:

1) negative (because the satellite is on a bound orbit)

2) inversely proportional to the distance of the satellite from the Earth's center, R+h

So the magnitude of the fraction in the equation is larger for the satellite which is closer to the Earth's surface (satellite A), but since the energy is negative, this means that the total energy of this satellite is smaller than that of satellite B. So, satellite B has a greater total energy.

(d) 1.03\cdot 10^7 J

We have to calculate the total energy of each satellite.

Given:

G=6.67\cdot 10^{-11}

M=5.98\cdot 10^{24} kg

m = 12.0 kg

R+h_A = 6370 km+5920 km=12290 km = 12.3 \cdot 10^6 m

R+h_B = 6370 km+19600 km=25970 km = 26.0 \cdot 10^6 m

We find:

E_A = - \frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(12.0)}{2(12.3\cdot 10^6)}=-1.95\cdot 10^{7} J

E_B = - \frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(12.0)}{2(26.0\cdot 10^6)}=-9.2\cdot 10^{6} J

So the difference in total energy is

E_B-E_A = -9.2\cdot 10^6 - (-1.95\cdot 10^7) =1.03\cdot 10^7 J

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Artist 52 [7]
A tissue donor is what you're probably looking for. :)
8 0
4 years ago
A motorcycle has a constant speed of 29.6 m/s as it passes over the top of a hill whose radius of curvature is 183 m. The mass o
coldgirl [10]

Answer:

a) centripetal force = m v^2 / R = 329 * (29.6 m/s)^2 / 183

F = 1580 Newtons

b) normal force = gravitational force - F = 329 * 9.8 - 1580 = 1640 N

8 0
2 years ago
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