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4 years ago

6

How does the mass of an object affect its acceleration during free fall

2 answers:

ira [324]4 years ago

8 0

The mass of an object has no effect whatsoever on the object's
acceleration during free-fall. If there is no air resistance to interfere
with the natural effects of gravity, then a feather and a battleship ...
dropped at the same time ... fall together, and hit the ground at the
same time.

natali 33 [55]4 years ago

5 0

It doesn't. If you took a watermelon and an orange and dropped them at the same time, they would fall the same speed snd land (or squash) at the same time. Try it. It doesn' have to be those two fruits.

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A grocery shopper tosses a(n) 8.5 kg bag of rice into a stationary 17.7 kg grocery cart. The bag hits the cart with a horizontal

timama [110]

Answer:

2.2386 m/s

Explanation:

I think you would use the momentum equation.

m1v1=m2v2

m1= mass of the bag (8.5kg)

v1= speed of bag (6.9 m/s)

m2= mass of bag and cart (26.2 kg)

v2= speed of cart and bag

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4 years ago

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4 years ago

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vredina [299]

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3 years ago

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gizmo_the_mogwai [7]

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3 years ago

Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan

elena55 [62]

Answer:

$10.07m/s^2$

Explanation:

Information we have:

velocities:

initial velocity: $v_{i}=0mph$ (starts from rest)

final velocity: $v_{f}=50mph$

time: $t=2.22s$

Since we need the answer in $m/s^2$ , we nees to convert the speed to meters per second:

$v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s$

We find the acceleration with the following formula:

$a=\frac{v_{f}-v_{i}}{t}$

substituting the known values:

$a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2$

the acceleration is 10.07 $m/s^2$

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3 years ago

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