Answer:
-5 V
Explanation:
The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value
vb−va
is negative.
We can calculate the potential difference between the two points by using the law of conservation of energy:
![\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0](https://tex.z-dn.net/?f=%5CDelta%20K%2B%20%5CDelta%20U%3D0%5C%5C%5CDelta%20K%20%2B%20q%5CDelta%20V%3D0)
where:
is the change in kinetic energy of the particle
is the charge of the particle
is the potential difference
Re-arranging the equation, we can find the value of the potential difference:
![\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V](https://tex.z-dn.net/?f=%5CDelta%20V%3DV_b-V_a%20%3D%20-%5Cfrac%7B%5CDelta%20K%7D%7Bq%7D%3D-%5Cfrac%7B1.6%5Ccdot%2010%5E%7B-18%7D%20J%7D%7B3.2%5Ccdot%2010%5E%7B-19%7D%20C%7D%3D-5%20V)
The correct unit for the speed of light is [ m s⁻¹ ].
Time = (distance) / (speed)
Time = (9.3 x 10^7 miles) x (1609 m/mile) / (3 x 10^8 m/s) = 498.8 seconds .
That would be <em>8.31 minutes</em>.
Answer:
Explanation:
The time period of geosynchronous satellite must be equal to T .
The radius of its orbit will be ( R+ h )
orbital velocity V₀ = ![\sqrt{\frac{GM}{( R+h)} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BGM%7D%7B%28%20R%2Bh%29%7D%20%7D)
Time period T = 2π( R + h ) / V₀
= 2π( R + h ) x ![\sqrt{\frac{( R+h)}{GM } }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B%28%20R%2Bh%29%7D%7BGM%20%7D%20%7D)
= R +h
h =
- R.
Answer:
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Answer:
3.82 Ns
Explanation:
Time varying horizontal Force is given as
F(t) = A t⁴ + B t²
F(t) = 4.50 t⁴ + 8.75 t²
Impulse imparted is given as
![I = \int_{0}^{t}Fdt](https://tex.z-dn.net/?f=I%20%3D%20%5Cint_%7B0%7D%5E%7Bt%7DFdt)
![I = \int_{0}^{1}Fdt](https://tex.z-dn.net/?f=I%20%3D%20%5Cint_%7B0%7D%5E%7B1%7DFdt)
![I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt](https://tex.z-dn.net/?f=I%20%3D%20%5Cint_%7B0%7D%5E%7B1%7D%284.50%20t%5E%7B4%7D%20%2B%208.75%20t%5E%7B2%7D%29dt)
![I = ((0.9) (1)^{5} + (2.92) (1)^{3})](https://tex.z-dn.net/?f=I%20%3D%20%28%280.9%29%20%281%29%5E%7B5%7D%20%2B%20%282.92%29%20%281%29%5E%7B3%7D%29)
![I = 3.82 N-s](https://tex.z-dn.net/?f=I%20%3D%203.82%20N-s)