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Sergeeva-Olga [200]
4 years ago
8

How many atoms are there in 3.4moles if helium ,show the calculation

Physics
1 answer:
prohojiy [21]4 years ago
6 0
Answer: 20.4752789138x x  10^23 atoms
To count how many atoms in moles you need to know Avogadro's number. Avogadro's number dictate that for every mole there is 6.022140857 × 10^23 molecule/atoms.
Then 3.4 moles of helium will be 3.4x 6.022140857 x  10^23 atoms= 20.4752789138x x  10^23 atoms
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The tendency of two masses alone in the universe to drift together is a result of
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3 years ago
Read 2 more answers
One heater uses 310 W of power when connected by itself to a battery. Another heater uses 180 W of power when connected by itsel
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Answer:

55.8W

Explanation:

P= V^2/R

R= V^2/P

For series connection

Req= R1+ R2= V^2/310 + V^2/180

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But V^2 will cancel out

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3 years ago
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An earth satellite remains in orbit at a distance of 13300 km from the center of the earth. what is its period? the universal gr
iren [92.7K]
Given: Altitude of satellite r = 13,300 Km convert to meter

                                          r = 1.33 x 10⁷ m

Universal Gravitational constant G = 6.67 x 10⁻¹¹ N.m²/Kg²

Mass of the earth Me = 5.98 x 10²⁴ Kg

Required: Period of satellite   T = ?

Formula: F = ma;   Centripetal acceleration ac = V²/r    F = GMeMsat/r²

Velocity of satellite V = 2πr/T

equate T from all given equation.

F = ma

GMeMsat/r² = MsatV²/r  cancel Msat and insert V = 2πr/T

GMe/r² = (2πr)²/rT²  Equate T or period of satellite

T² = 4π²r³/GMe

T² = 39.48(1.33 X 10⁷ m)³/(6.67 x 10⁻¹¹ N.m²/Kg²)(5.98 x 10²⁴ Kg)

T² = 9.29 x 10²² m³/3.99 x 10¹⁴ m³/s²

T² = 232,832,080.2 s²

T = 15,258.84 seconds       or (it can be said around 4.24 Hr)





3 0
4 years ago
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