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lozanna [386]
3 years ago
13

Material A has a higher thermal conductivity than Material B. Which material will transfer energy by conduction faster?​

Physics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer: a

Explanation:

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ivanzaharov [21]
C. cooked noodles and water
because noodles are long and water has no shape or size.
if you have any problems with this answer,
comment and I will fix it.
Thank s!
6 0
3 years ago
What is the force on an object that accelerates at 2 m/s/s and has a mass of 120 kg
11111nata11111 [884]

Answer:

240 Newtons

Explanatiohn:

f = m × a

f = 120 × 2

f = 240 Newtons

<h3>The force is 240 Newtons</h3>
6 0
3 years ago
What influences the path that surface currents take?
Anastasy [175]
The answer is wind forces and Earth’s rotation
8 0
3 years ago
Read 2 more answers
We need to find the launch velocity of our new marble launcher. we know that it will launch a 25g marble to a distance of 73 cm,
White raven [17]

The launch velocity of the marble launcher is 34.65 m/s

Given that the launch velocity of marble launcher, launches a 25g marble to a distance of 73 cm (0.73 m) and the marble roll up to 6.2 meters before stopping. The launch height is 20 cm (0.2 m).

The time for landing can be calculated by the second equation of motion formula:

h = ut + \frac{1}{2}gt^{2}

Let u = 0

0.2 = 0×t + \frac{1}{2} × 9.8 × t^{2}

t^{2} = \frac{0.2}{4.9}

t^{2} = 0.04

t = 0.2s

Now, the launch velocity of the marble launcher can be calculated by:

Speed = Distance / Time

Speed = \frac{0.73 + 6.3}{0.2}

Speed = \frac{6.93}{0.2}

Speed = 34.65 m/s

Therefore, the launch velocity of the marble launcher is 34.65 m/s

Know more about Launch velocity: -brainly.com/question/18883779

#SPJ9

3 0
1 year ago
A parallel-plate capacitor consists of a set of two parallel plates of area A separated by a distance d. This capacitor is conne
icang [17]

Answer:

1) the capacitance of the capacitor increases. This is due to the induction of opposite charges on the two surfaces of the dielectric by the plate, this increased the charge in the field, from C =Q/v, it is seen that capacitance C will increase with increase in Q since v is constant.

2) the electric field intensity will also increase with increase in electric charges provided plate separation d remains constant.

7 0
3 years ago
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