Answer:
B. Ultraviolet.
Explanation:
Io is the fourth smallest moon in the Galilean moons and it is the innermost moon out of the other three moon. It has the highest density as compare to the moon and it has lowest water at its surface.
While it is Jupiter moon it leaves a footprint of magnet over the Jupiter's upper atmosphere. The appearance of this moon look like as a spot of ultraviolet emission that remains fixed underneath Io as Jupiter rotates. So it reflects Ultraviolet radiations.
An object of mass
is moving with a uniform velocity of
. The kinetic energy possessed by the object is
.
Given:
Mass of an object 
Velocity 
Kinetic Energy
Mass of Object 
Kinetic Energy 
Kinetic Energy 
What is Kinetic Energy?
- In physics, an object's kinetic energy is the energy it has as a result of its motion.
- It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.
- The body retains its kinetic energy after gaining it during acceleration until its speed changes.
- Kinetic energy is present in a speeding bullet, a walking human, and electromagnetic radiation such as light. The energy associated with the continual, random bouncing of atoms or molecules is another type of kinetic energy.
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I would go with b because the seasons are caused by the tilt of Earth axis, not greenhouse gases
Answer:
+5.7 m/s
Explanation:
According to the law of conservation of momentum is that the momentum before the collision is equal to the momentum after the collision. In an equation form it would look like this:
M₁V₁+M₂V₂ = M₁V₁'+M₂V₂'
Where:
M₁ = mass of object 1 (kg)
V₁ = velocity of object 1 before the collision (m/s)
V₁' = Final velocity of object 1 after the collision (m/s)
M₂ = mass of object 2 (kg)
V₂ = velocity of object 2 before the collision (m/s)
V₂' = Final velocity of object 2 after the collision (m/s)
According to your problem you have the following given:
M₁ = 5 g = 0.005kg
V₁ = 3 m/s
V₁' = -5m/s (It bounced off so it is going the other direction)
M₂ = 6g = 0.006kg
V₂ = -1 m/s (It is coming from the opposite direction of the 3-ball)
V₂' = ?
So we plug in what we know and solve for what we don't know.

Answer:The buoyant force doesn't depend on the overall depth of the object submerged. In other words, as long as the object is fully submerged, bringing it to a deeper and deeper depth will not change the buoyant force. This might seem strange since the pressure gets larger as you descend to deeper depths.: