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uranmaximum [27]
3 years ago
11

Wo gravitational forces act on a particle, in perpendicular directions. to find the net force, can we add the magnitudes of thos

e two forces?
Physics
1 answer:
son4ous [18]3 years ago
3 0
No, you can not. 

f=mxa
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A girl (mass M) standing on the edge of a frictionless merry-go-round (radius R, rotational inertia I) that is not moving. She t
vladimir1956 [14]

a) \omega=\frac{-mvR}{I+MR^2}

b) v=\frac{-mvR^2}{I+MR^2}

Explanation:

a)

Since there are no external torques acting on the system, the total angular momentum must remain constant.

At the beginning, the merry-go-round and the girl are at rest, so the initial angular momentum is zero:

L_1=0

Later, after the girl throws the rock, the angular momentum will be:

L_2=(I_M+I_g)\omega +L_r

where:

I is the moment of inertia of the merry-go-round

I_g=MR^2 is the moment of inertia of the girl, where

M is the mass of the girl

R is the distance of the girl from the axis of rotation

\omega is the angular speed of the merry-go-round and the girl

L_r=mvR is the angular momentum of the rock, where

m is the mass of the rock

v is its velocity

Since the total angular momentum is conserved,

L_1=L_2

So we find:

0=(I+I_g)\omega +mvR\\\omega=\frac{-mvR}{I+MR^2}

And the negative sign indicates that the disk rotates in the direction opposite to the motion of the rock.

b)

The linear speed of a body in rotational motion is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the body from the axis of rotation

In this problem, for the girl, we have:

\omega=\frac{-mvR}{I+MR^2} is the angular speed

r=R is the distance of the girl from the axis of rotation

Therefore, her linear speed is:

v=\omega R=\frac{-mvR^2}{I+MR^2}

5 0
3 years ago
Paul lifts a sack weighing 245 newtons vertically from the ground and places it on a platform at a height of 0.7 meters. If he t
d1i1m1o1n [39]

Answer:

B. 17.15 watts

Explanation:

Given that

Time = 10 seconds

height = distance = 0.7 meters

weight of sack = mg = F = 245 newtons

Power = work done/ time taken

Where work done = force × distance

Substituting the given parameters into the formula

Work done = 245 newton × 0.7 meters

Work done = 171.5 J

Recall,

Power = work done/time

Power = 171.5 J ÷ 10

Power = 17.15 watts

Hence the power expended is B. 17.15 watts

6 0
3 years ago
The tilt of the Earth's axis of rotation changes from approximately 22.5° to 24.5° over a period of 41,000 years. This causes gl
kompoz [17]
<span>b. less climatic variation between the summer and winter seasons in the middle and high latitudes

As the tilt becomes higher (approaches 24 degrees) there is greater variation between the summer and winter months, due to the fact that the tilt toward the sun in the summer and away from the sun in the winter are more pronounced. </span>
3 0
3 years ago
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Object A and Object B are 100 meters apart. If Object A gains some
satela [25.4K]

The gravitational force between the two objects A) It increases.

Explanation:

The gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2} (1)

where

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

In this problem, object A and object B are initially at a distance of

r = 100 m

And at that distance, the force between them is

F

Later, object A gains some mass. We notice from eq.(1) that the gravitational force is directly proportional to the mass: therefore, if the mass of either of the two objects increases, then the gravitational force between them also increases. Therefore, the new force will be larger than the original force:

F' > F

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

7 0
3 years ago
What must two objects have for gravity to exist between them
Musya8 [376]
The two factors are mass and distance between them.
3 0
3 years ago
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