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nalin [4]
3 years ago
8

A student made a model of an onion skin cell she viewed using a microscope. The scale is 1:500.The students cell model has a len

gth of 15cm. How many centimeters is the real cells length?
Physics
2 answers:
coldgirl [10]3 years ago
7 0

Answer: 0.03 cm

Explanation:

I'm taking the test on apex and I had to guess

r-ruslan [8.4K]3 years ago
6 0
The original will be 15\500 to find the real length
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Answer:

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

Explanation:

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PE₁ + KE₁ = PE₂ + KE₂

mgh₁ + ½mv₁² = mgh₂ + ½mv₂²

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What kind of fluctuations in weather patterns do you expect to see in your area? Will the fluctuations or changes vary by month,
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6 0
3 years ago
Two forces P and Q act on an object of mass 15.0 kg with Q being the larger of the two forces. When both forces are directed to
Rom4ik [11]

Answer:

P=6.25N  and Q=16.25N

Explanation:

In order to solve this problem we must first draw a free body diagram for both situation, (see attached picture).

Now, we need to analyze the two free body diagrams. So let's analyze the first diagram. Since the body is accelerated, then the sum of forces is equal to mass times acceleration, so we get:

\Sigma F=ma

We can assume there will be only the two mentioned forces P and Q, so

the sum of forces will be:

P+Q=ma

P+Q=(15kg)(1.50m/s^{2})

P+Q=22.5N

We can do the same analysis for the second free body diagram:

\Sigma F=ma

Q-P=(15kg)(0.7m/s^{2})

Q-P=10.5N

so now we have a system of equations we can solve by elimination:

Q+P=22.5N

Q-P=10.5N

Now, we can add the two equations together so the P force is eliminated, so we get:

2Q=32.5N

now we can solve for Q:

Q=\frac{32.5N}{2}

so

Q=16.25N

Now we can use any of the equations to find P.

Q+P=22.5N

P=22.5N-Q

when substituting for Q we get:

P=22.5N-16.25N

so

P=6.25N

5 0
4 years ago
When a gas is heated, it absorbs 196 joules of heat from the surroundings. At the same time, the gas expands, doing pressure-vol
timurjin [86]

Answer:

(a) q positive; w negative.

(b) ΔE = -126 J

(c) E and ΔE

Explanation:

<em>(a) Determine whether the amounts of heat (q) and work (w) exchanged should have positive or negative signs. heat (q) positive negative work (w) positive negative</em>

By convention, when the system absorbs heat from the surroundings, its sign is positive, that is, q = 196 J.

By convention, when the system exerts work on the surroundings, its sign is negative, that is, w = -322 J.

<em>(b) Calculate the change in internal energy (ΔE) of the gas. J</em>

The change in internal energy (ΔE) can be calculated using the following expression.

ΔE = q + w

ΔE = 196 J + (-322 J) = -126 J

<em>(c) Determine whether one or more of the following is a state function: </em>

<em> internal energy (E) of a system, </em>

<em>change in internal energy (ΔE) of a system, </em>

<em>heat (q) absorbed or released by a system, </em>

<em>work (w) done on or by a system.</em>

<em />

E and ΔE are state functions (they only depend on the states of the gas), whereas q and w depend on the trajectory.

7 0
3 years ago
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