**Answer:**

**The conductivity of Nichrome is ****.**

**Explanation:**

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² **[1 mm² = 10⁻⁶ m²]**

We know, from **Ohm's law,** **that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. **Therefore, the resistance of the nichrome wire is given as:

Now, **resistance of the nichrome wire in terms of its resistivity, length and area of cross section is given as:**

Where,

Now, plug in all the values given and solve for . This gives,

Now, **conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:**

Conductivity is measured in Siemens per meter (S/m)

Therefore, **the conductivity of Nichrome is ****.**