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Ierofanga [76]
3 years ago
12

(3.8 * 10^-2 cm) * (4.4 * 10^-2 cm) * (7.5 * 10^2 cm)

Physics
1 answer:
Marysya12 [62]3 years ago
4 0

Answer:

1.254 cm

Explanation:

(3.8 * 10^-2 cm) = 0.038 cm

(4.4 * 10^-2 cm) = 0.044 cm

(7.5 * 10^2 cm) = 750 cm

0.038 * 0.044 * 750 = 1.254 cm

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A volume variance is the difference between overhead at maximum production volume and that at the budgeted production volume.
umka21 [38]
The statement is not correct. Therefore, the answer is letter B. False. The actual definition of a volume variance is that it is the difference of the quantity consumed and the amount budgeted to be sold, the difference will furthermore be multiplied to the standard unit per price. 
3 0
3 years ago
At what angle torque is half of the max
denis-greek [22]
At what angle torque is half of max
8 0
3 years ago
imagine that 501 people are present in a movie theater of volume 8.00 x10^3 that is sealed shut so no air can escape. Each perso
Semenov [28]

Answer:

The temperature of air will increase by \Delta T=41044.967\ K

Explanation:

Given:

  • no. of person in a theater, n=501
  • volume of air in the theater, V=8\times 10^3\ m^3
  • rate of heat given off by each person, P=110\ J.s^{-1}
  • duration of movie, t=2\ hr=7200\ s
  • initial pressure in the theater, p_i=1.01\times 10^5\ Pa
  • initial temperature in the theater, T_i=20+273=293\ K
  • specific heat capacity of air at the given conditions, c=1.0061\ J.kg^{-1}.K^{-1}

<u>The total quantity of heat released by the total people in the theater during the movie:</u>

Q=n.P.t

Q=501\times 110\times 7200

Q=396792000\ J

<u>Form the relation of heat capacity:</u>

Q=m.c.\Delta T

∵p_i.V=m.R.T

Q=(\frac{p_i.V}{R.T}) \times c\times (T_f-T_i)

396792000=(\frac{1.01\times 10^5\times 8\times 10^3}{287\times 293}) \times 1.0061\times (T_f-293)

T_f=41337.967\ K

Change in temperature of air:

\Delta T=41044.967\ K

8 0
3 years ago
An electric dipole is formed from two charges, ±q, spaced 0.800 cm apart. The dipole is at the origin, oriented along the y-axis
Simora [160]

Answer: q = 2.781e-9C = 2.781nC

E=200C

Explanation:

E = Qd/(2πEor^3)

Where

E=Electric field intensity

Q=Charge

d=distance between the dipole=0.008m

Eo=permitivitty

400 N/C = Q(0.80e-2 m)/(2πε*(10e-2 m)^3)

Q= (400* 2* 3.142 * 8.85 x 10-12 * 0.1^3)/0.008

q = 2.781e-9C = 2.781nC

b)

Though the dipole are two separate charges. And since the point is on the x-axis, the electric field strengths are equivalent. The magnitude of the vector sum is:

E = kq*2sin θ/r^2

= 2(8.99e9 N*m^2/C^2)(2.781e-9 C)*sin(arctan(.4/10))/(10e-2 m)^2

= 2(8.99e9) * (2.781e-9) * sin(2.290)/(10e-2 m)^2

=200 C

3 0
3 years ago
If you jump off a 10 m diving platform, how long will it take you to hit the water?
Vilka [71]

Answer:

<h2>t=1.43 s</h2>

Option A is the correct option.

Solution,

S=10 m

u=0 m/s

a=9.8 m/s^2

Now,

<h3>2s = a {t}^{2}  \\ or \:  {t}^{2}  =  \frac{2 \times 10}{9.8}  \\ or \:  {t}^{2}  =  \frac{20}{9.8}  \\ or \:  {t}^{2}  = 2.04 \\ or \: t =  \sqrt{2.04}  \\ t = 1.43 \: seconds</h3>

hope this helps...

Good luck on your assignment...

8 0
3 years ago
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