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Ierofanga [76]
3 years ago
12

(3.8 * 10^-2 cm) * (4.4 * 10^-2 cm) * (7.5 * 10^2 cm)

Physics
1 answer:
Marysya12 [62]3 years ago
4 0

Answer:

1.254 cm

Explanation:

(3.8 * 10^-2 cm) = 0.038 cm

(4.4 * 10^-2 cm) = 0.044 cm

(7.5 * 10^2 cm) = 750 cm

0.038 * 0.044 * 750 = 1.254 cm

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the atomic number of cesium (Cs) is 55. If an atom of cesium has 78 neutrons, what is the atomic mass of cesium?
Slav-nsk [51]
Atomic mass= number of protons + number of neutrons
55 + 78 = 133
hope this helps
7 0
3 years ago
Read 2 more answers
Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar
lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
  • The tension in the string, T=16 N, downward

Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

a=3.5 m/s^2 is the acceleration (upward)

Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

brainly.com/question/11411375

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#LearnwithBrainly

7 0
4 years ago
A small candle is 38 cm from a concave mirror having a radius of curvature of 24 cm. (a) what is the focal length of the mirror?
Finger [1]
For a concave mirror, the radius of curvature is twice the focal length of the mirror:
r=2f
where f, for a concave mirror, is taken to be positive.

Re-arranging the formula we get:
f= \frac{r}{2}
and since the radius of curvature of the mirror in the problem is 24 cm, the focal length is
f= \frac{24 cm}{2} = 12 cm

8 0
4 years ago
How to solve <br>9.8 = (x-0) =?<br> 4.3​
Nadya [2.5K]
You want to know how to solve it?
7 0
3 years ago
The disks you will be using in the lab have the following parameters. All disks are solid with outer radius R1 = 0 0632 m and in
Nesterboy [21]

Answer:

MT disc   I = 2,752 10-3 kg m²

MB disc   I = 2,726 10⁻³ kg m²

Explanation:

The moment of inertia given by the expression

        I = ∫ r² dm

for bodies with high symmetry it is tabulated

  for a hollow disk it is

        I = ½ M (R₁² + R₂²)

let's apply this equation to our case

disc MT = 1,357 kg

         I = ½ 1,357 (0.0079² + 0.0632²)

         I = 2,752 10-3 kg m²

disk MB = 1,344 kg

         I = ½ 1,344 (0.0079² + 0.0632²)

         I = 2,726 10⁻³ kg m²

4 0
3 years ago
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