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3 years ago

Need help ASAPPPPPP will mark brainleast if right no links or im reporting

Physics

2 answers:

kykrilka [37]3 years ago

5 0

Answer: Density--> the amount of mass in a given volume

Boiling point: the tempeture when a liquid becomes gas

Conductivity: the ability of a subtance to transfer heat or electricety

Bouyant force: The upward force of an object in a liquid

soulibility: the ability of a subtance to disolve in other.

sorry for bad spelling

Explanation:

shepuryov [24]3 years ago

5 0

Answer:

Hey there

Boiling point-the temperature at which liquid becomes gas.*

*for water that is 100 c*

Density-the amount of gas in a given volume.**

** the density of water is 997kg/m³

Soliditiy-the ability of a substance to dissolve in another.***

***You would dissolve if you were inside the sun.

Conductivity-the ability of a substance to transfer heat or electricity.****

****metal transfers both heat and electricity efficiently.

Buoyant force-the upward force on an object in a fluid.*****

*****You float in water because you are lighter than water.

Hope it helped

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Vladimir79 [104]

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3 years ago

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lakkis [162]

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3 years ago

From the top of a cliff overlooking a lake, a person throws two stones. The two stones have identical initial speeds of v0 = 13.

Alina [70]

Answer:

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Explanation:

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g = 9.8 m/s²

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4 years ago

Find the specific heat of a substance that requires 8000 J of energy to heat up 400g by 20 C?

monitta

Answer:

$c=1\ J/g^\circ C$

Explanation:

Given that,

Heat required, Q = 8000 J

Mass, m = 400 g

The change in temperature, $\Delta T = 20^{\circ}$

The heat required due to change in temperature is given by :

$Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{8000 }{400\times 20}\\\\c=1\ J/g^\circ C$

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3 years ago

An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m

lesya [120]

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$P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)$

Using the Velocity Hourly Equation, we get:

$V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}$

Uniting the equations:

$\Delta t= \frac{V}{g(sen\O-ucos\O)}$

Entering the unknowns:

$\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)} \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)} \\ \Delta t= \frac{12}{5.27} \\ \boxed {\Delta t=2.28s}$

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0

3 years ago