Answer:
25.6 m/s
Explanation:
Draw a free body diagram of the sled. There are two forces acting on the sled:
Normal force pushing perpendicular to the hill
Weight force pulling straight down
Take sum of the forces parallel to the hill:
∑F = ma
mg sin θ = ma
a = g sin θ
a = (9.8 m/s²) (sin 38.0°)
a = 6.03 m/s²
Given:
v₀ = 0 m/s
a = 6.03 m/s²
t = 4.24 s
Find: v
v = at + v₀
v = (6.03 m/s²) (4.24 s) + (0 m/s)
v = 25.6 m/s
the answer is C because i did it and got it right
speed of the striking object is given as
now this speed in SI units given as
So here we can use kinematic now to find the height from where it is dropped
so here we will have
now we have
now from above equation
now we know that average height of 1 story building is 3 meter
so approx total number of stories in the building will be
Answer:
The potential will be Va/b
Explanation:
So Let sphere A charged Q to potential V.
so, V= KQ/a. ....(1
Thus, spherical shell B is connected to the sphere A by a wire, so all charge always reside on the outer surface.
therefore, potential will be ,
V ′ = KQ/b = Va/b... That is from .....(1), KQ=Va]
We know, v² - u² = 2as
Here, u = 0 [ Free fall ]
a = 9.8 m/s² [ Constant value for Earth System ]
s = 2.5 m
Substitute their values,
v² - 0 = 2 * 9.8 * 2.5
v² = 49
v = √49
v = 7 m/s
In short, Your Answer would be Option B
Hope this helps!