A gas under constant pressure has a volume of 30.57 m and a

1 answer:

6 0

Considering the relationship between volume and temperature, a gas under constant pressure can only have its volume reduced as a result of a decrease in its temperature.

According to Charles law, at constant pressure, the volume of a gas is directly proportional to its absolute temperature. Thus:

V1/T1 = V2/T2 where V1 = intial volume, V2 = final volume, T1 = initial temperature, and T2 = final temperature.

In this case, T1 = 59.0, V1 = 30.57, and V2 = 21.14

T2 = 21.14 x 59/30.57

= 20.05 K

It can be seen that the temperature of the gas has reduced from 59.0 K to 20.05K.

More on gas laws can be found here: brainly.com/question/1190311

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Can someone show their work on how to do this: Calculate the number of moles of Al2O3 present in 23.87g. (Molar mass of Al2O3= 1

vodomira [7]

Answer:

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moles of Al2O3 = 23.87g / 102.0g/mol

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2 years ago

what is the structure of XeO2F2???i know its hybridization as sp3d but cannot quite understand its diagram in free space,help an

skelet666 [1.2K]

The shape of XeO₂F₂ is Trigonal bi-pyramidal see-saw tetrahedron (see attached pictures)
- As you said the hybridization of Xe here is sp³d so its geometry has to be Trigonal bi-pyramidal in which F atom located on axial positions but for the final shape we exclude lone pair on Xe to give see-saw shape (see second picture)
- Remember that we have 5 pairs (4 bond pairs + 1 lone pair) and we have to place lone pair at equatorial position.