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3 years ago

1. Is O2 a compound? Explain.

1 answer:

4 0

1. O2 is not a compound because it only contains one or more type of the same element atom.
2. O2 is a molecule because a molecule is one or more of the same element atom.
3. The law of conversion is that the mass of the system will stay the same when transfer takes place. Like if you had an equation O+H2—> H2O the mass will remain the same.

4. It will be equal to 10 because of law of conservation of matter.

5. One observation can be that the compound, reaction you’re observing, has change states.

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Lunar Eclipse. Choose ALL that apply

antoniya [11.8K]

Answer:

b and a i jus did it

Explanation: none

6 0

3 years ago

Read 2 more answers

The following information was recorded by a student team working to prepare nickel sulfate. Plan: Prepare NiSO4 by reacting NiO

mixas84 [53]

Answer:

The options e and d are correct.

Explanation:

Mass of NiO = 7.5 g

Moles of NiO = $\frac{7.5 g}{74.69 g/mol}=0.10 mol$

Moles of sulfuric acid = n

Volume of sulfuric acid ,V= 50 mL = 0.050 L

Molarity of sulfuric acid ,M = 6 mol/L

$n=M\time V=6mol/L\times 0.050 L =0.3 mol$

$NiO + H_2SO_4\rightarrow NiSO_4 + H_2O$

According to reaction, 1 mole of NiO reacts with 1 mole of sulfuric acid.

Then 0.10 moles of NiO reacts with :

$\frac{1}{1}\times 0.10 mol/=0.10 mol$ of sulfuric acid.

As we can see that sulfuric acid is in excess amount, so the amount of the product will depend upon amount of NiO.

According to reaction, 1 mole of NiO gives with 1 mole of $NiSO_4$ .

Then 0.10 moles of NiO wil give :

$\frac{1}{1}\times 0.10 mol/=0.10 mol$ of $NiSO_4$ .

Molar mass of $NiSO_4$ = 154.75 g/mol

Mass of 0.10 moles of $NiSO_4$ :

= 154.75 g/mol × 0.10 mol = 15.475 g

Theoretical mass of $NiSO_4$ = 15.475 g

Experimental yield of $NiSO_4$ = 17.4 g

Percentage yield :

$\Yield=\frac{\text{Experimental mass}}{\text{Theoretical mass}}\times 100$

Percentage yield of $NiSO_4$ :

$\Yield=\frac{17.4}{15.475 g}\times 100=112\%$

Moles of $NiSO_4.6H_2O$ = 262.85 g/mol × 0.10 mol = 26.285 g

Experimental yield of $NiSO_4.6H_2O$ = 17.4 g

Percentage yield of $NiSO_4.6H_2O$ :

$\Yield=\frac{17.4}{26.285 g}\times 100=66.2\%$

3 0

3 years ago

Need help please omg Perform each of the following conversions being sure to set up the appropriate conversion factor in each ca

sertanlavr [38]

Answer:

The answer to your question is:

a) 31.75 cm

b) 0.475 miles

c) 2.44 yards

d) 11496.04 inches

Explanation:

Convert

a) 12.5 in to cm

1 in ------------------- 2.54 cm

12.5 in ---------------- x

x = 12.5(2.54)/1 = 31.75/ = 31.75 cm

b) 2513 ft to miles

1 mile -------------- 5280 ft

x miles ------------ 2513 ft

x = 2513(1)/5280 = 0.475 miles

c) 2.23 m to yards

1 m ------------- 1,094 yards

2.23 m ---------- x

x= 2.23x1.094/1 = 2.44 yards

d) 292 m to inches

1 m ---------------- 39.37 inches

292 m ------------- x

x = 292 x 39.37/1 = 11496.04 inches

6 0

3 years ago

A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol

astraxan [27]

Answer:

Volume of the $CO_{2}$ gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

$\frac{V}{T} =\frac{v}{t}$

where , V= initial volume v= final volume

T=initial temperature t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K (since converting celsius into kelvin that

is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

$\frac{240ml}{295K} =\frac{v}{317K}$

240ml x317K = v x 295K (through cross multiplication )

v = $\frac{240ml\times317K}{295K}$

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

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3 years ago

Por que los egipcios podrían haber construido pirámides?

kicyunya [14]

Eran monumentos funerarios, de manera que su principal función era la de acoger tumbas de los faraones para que el viaje al cielo fuese más sencillo

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3 years ago